All categories

3 years ago

PLEASE HELPPP

Mathematics

1 answer:

Setler79 [48]3 years ago

7 0

There are three prime numbers and 3 even numbers on a number cube, so the probability of each is 3/6 = 1/2.

You might be interested in

How do you solve for y in the equation: <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%7D%7By%7D%20%3Dy-6" id="TexFormula1" title

kozerog [31]

No it isn't.

Explanation:

x/y * y = (y-6) * y

x = y^2 - 6y

A function gives just one y for every x

In this case there will always be 2 y's for every x

Example:

y can be

y = 6

y =−6

(0,-6) & (0,6)

5 0

3 years ago

NEED HELP ASAP!!!! Due by 4!!!! The question is the triangle find x

sashaice [31]

It’s 15x plus 1 I believe it is the sender

5 0

3 years ago

There are about 16 kilometers in 10 miles. About how many kilometers are in 5 miles

SSSSS [86.1K]

Answer:

8.04672

or 8

Step-by-step explanation:

4 0

2 years ago

The prodoct of 4 and number plus 17 is 5

vichka [17]

Answer:

-3

Step-by-step explanation:

The product (the result of a multiplication) of 4 and a number. Let x be the unknown number:

4 · x = 4x

Plus 17:

4x + 17

Is 5:

4x + 17 = 5

Solve:

4x = 5 - 17

4x = -12

x = -12 ÷ 4

x = -3

3 0

3 years ago

Read 2 more answers

An insurance company selected a random sample of 500 clients under 18 years of age and found that 180 of them had had an acciden

adoni [48]

Answer: The accident proportion differ between the two age groups is 0.11.

Step-by-step explanation:

Since we have given that

Number of clients under 18 years of age = 500

Number of clients had had an accident = 180

Proportion of client had an accident = $\dfrac{180}{500}=\dfrac{18}{50}$

Number of clients aged 18 and older = 600

Number of clients had had an accident = 150

Proportion of client had an accident = $\dfrac{150}{600}=\dfrac{15}{60}$

So, According to question, we get that

Difference between the two age groups proportions would be :

$\dfrac{18}{50}-\dfrac{15}{60}\\\\=\dfrac{108-75}{300}\\\\=\dfrac{33}{300}\\\\=\dfrac{11}{100}$

Hence, the accident proportion differ between the two age groups is 0.11.

8 0

2 years ago