Answer:
see explanation
Step-by-step explanation:
I don't have graphing facilities but can give you the vertex and 1 other point.
Given a parabola in standard form
y = ax² + bx + c ( a ≠ 0 )
Then the x- coordinate of the vertex is
x = - 
y = - x² - 2x + 8 ← is in standard form
with a = - 1 and b = - 2 , then
x = -
= - 1
Substitute x = - 1 into the equation for corresponding value of y
y = - (- 1)² - 2(- 1) + 8 = - 1 + 2 + 8 = 9
vertex = (- 1, 9 )
To obtain another point substitute any value for x into the equation
x = 0 : y = 0 - 0 + 8 , then (0, 8 ) is a point on the graph
x = 2 : y = - (2)² - 2(2) + 8 = - 4 - 4 + 8 = 0 then (2, 0 ) is a point on the graph
Y = mx + b
m represents the slope
b represents the y intercept
7.5795 ounces of the bar are silver.
Answer: I have the pictures attached
Step-by-step explanation:
In order to graph this, we have to get it into this equation: y = mx + b, where m = slope and b = y intercept.
y = 3/2x - 4 is already in this form.
2y + 4 = 2 + 3x is not, so we have to isolate y
2y + 4 - 4 = 2 + 3x - 4
2y = -2 + 3x
2y/2 = -2/2 + 3x/2
y = -1 + 3/2x
y = 3/2x - 1
Okay, now graph it knowing your y intercepts and your slopes.