Answer:
16 and 4
Step-by-step explanation:
Let (x+y) =20 and (x-y)=12 then:
Isolate for x in each equation
x=20-y and x=12+y
Set the equations to equal each other since the value of x should be the same for both
20-y = 12+y
Rearrange so that y is on one side and the numbers are on the other
8 = 2y
y= 8/2
y= 4
Now substitute the y- value back into either of the original equations
x+y= 20
x+4 = 20
Rearrange and isolate x
x = 20-4
x = 16
So the two values are 16 and 4
Answer: y = -4/5x - 12
1. First find slope. Since you are trying to find a line perpendicular to y = 5/4x + 10, the slope would be the negative reciprocal of 5/4x.
slope = - 4/5x
2. plug in (-5,-8) and the slope of -4/5 to the point slope form equation
(y-y2) = slope (x-x2)
= y+8=-4/5(x+5)
3. solve and simply y+8=-4/5(x+5)
y = -4/5x - 12 is your answer
Answer:
D) x = -2/3 and x = 6
Step-by-step explanation:
4(x²−x+2)−(x+10)(x+2) Distribute
(4)(x²) + (4)(−x) + (4)(2) + − x² + −12x + −20 Multiply
4x² + −4x + 8 + −x² + −12x + −20 Combine like terms
(4x² + −x²) + (−4x + −12x) + (8 + −20) Combine like terms
3x² −16x −12 = 0
x = -2/3 and x = 6
I graphed the equation on the graph below.
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