Answer:
If Hunter is right beneath Graham ( 18ft-5ft=13ft) and G's arms are 18ft above ground ( and going up, no bending) the question would be at what hight would Graham catch the ball and and how soon.
The maximum hight that the ball can reach before falling ( when the vector F - force of throwing the ball to Graham, would be equal in module to gravitational force - considering gravitational velocity of 13ft/s^2
I think the answer is A, correct me if I’m wrong :)
The order of operations are different. Hence, the answers are not equal
Explanation:
Oder of operations using PEMDAS (Parenthesis, Exponent, Multiplication, Division, Addition, Subtraction)
[(12÷(2 + 2)]³ and (12 ÷ 2) + 2³
we solve seperately:
[(12÷(2+ 2)]³
we solve the parenthesis first:
(12 ÷ 4)³
then we apply division:
= (3)³
Then expand the exponent:
= 27
(12 ÷ 2) + 2³
we solve the parenthesis first:
6 + 2³
we expand the exponent:
6 + 8
we apply addition:
14
The order of operations are differnt. Hence, the answers are not equal
Answer:
Cieee ketemu monyet kesesat
Step-by-step explanation:
Tolongin gw nyeth TvT
