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2 years ago

Find the missing right triangle side lengths in the models of the Pythagorean Theorem below

Mathematics

2 answers:

Sladkaya [172]2 years ago

8 0

Answer:

The picture on the left doesn’t have a right triangle.

maw [93]2 years ago

5 0

Answer: 24, 10, 26 and 4.6, 5, 6.7

Step-by-step explanation: for the first triangle the square with the area 576 has side lengths of 24 because 24 is the square root of 576, the square with the area 676 has a side length of 26 because 26 is the square root of 576, and we already know the side lengths of the third triangle are 10 for the second triange we know the side length of the square with the area 21 is about 4.6 because √21 ≈ 4.6 and the square with the area 25 the side length is 5 because √25 = 5 and the last square the side length is 6.7 because √46 ≈ 6.7

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If you know how to do this pls help thankyou!

dmitriy555 [2]

Answer : 49

I hope you understand sorry for the ugly writing

4 0

2 years ago

What is the measure of angle c?

s344n2d4d5 [400]

Answer:

50 degrees

Step-by-step explanation:

Okay! So first off, because this is NOT a right triangle, we can't use soh cah toa. That means we can either use the law of sines or the law of cosines.

Because we only have sides here and no angles, we are forced to use the law of cosines.

c^2 = a^2 + b^2 − 2ab cos(C)

c = 6

b = 7.5

a = 6.5

36 = 6.5^2 + 7.5^2 - 2(6.5)(7.5)cos(C)

36 = 98.5 - 97.5cos(C)

-62.5 = -97.5cos(C)

0.641 = cos(C)

angle C = cos^-1(0.641)

angle C = 50.13 which is around 50 degrees

Remember! A dumb thing i always used to do in geometry was use radians instead of degrees, be sure to use degrees here because you are looking for degrees. Radians are for things involving not degrees, but PI.

5 0

2 years ago

What is the domain of this function

Talja [164]

Answer:

I think its A

Step-by-step explanation:

8 0

2 years ago

PLEASE HELP MEEEE HURRRY!!! :)

sammy [17]

Answer:

Option D

Step-by-step explanation:

We are given the following equations -

$\begin{bmatrix}-5x-12y-43z=-136\\ -4x-14y-52z=-146\\ 21x+72y+267z=756\end{bmatrix}$

It would be best to solve this equation in matrix form. Write down the coefficients of each terms, and reduce to " row echelon form " -

$\begin{bmatrix}-5&-12&-43&-136\\ -4&-14&-52&-146\\ 21&72&267&756\end{bmatrix}$ First, I swapped the first and third rows.

$\begin{bmatrix}21&72&267&756\\ -4&-14&-52&-146\\ -5&-12&-43&-136\end{bmatrix}$ Leading coefficient of row 2 canceled.

$\begin{bmatrix}21&72&267&756\\ 0&-\frac{2}{7}&-\frac{8}{7}&-2\\ -5&-12&-43&-136\end{bmatrix}$ The start value of row 3 was canceled.

$\begin{bmatrix}21&72&267&756\\ 0&-\frac{2}{7}&-\frac{8}{7}&-2\\ 0&\frac{36}{7}&\frac{144}{7}&44\end{bmatrix}$ Matrix rows 2 and 3 were swapped.

$\begin{bmatrix}21&72&267&756\\ 0&\frac{36}{7}&\frac{144}{7}&44\\ 0&-\frac{2}{7}&-\frac{8}{7}&-2\end{bmatrix}$ Leading coefficient in row 3 was canceled.

$\begin{bmatrix}21&72&267&756\\ 0&\frac{36}{7}&\frac{144}{7}&44\\ 0&0&0&\frac{4}{9}\end{bmatrix}$

And at this point, I came to the conclusion that this system of equations had no solutions, considering it reduced to this -

$\begin{bmatrix}1&0&-1&0\\ 0&1&4&0\\ 0&0&0&1\end{bmatrix}$

The positioning of the zeros indicated that there was no solution!

<u><em>Hope that helps!</em></u>

6 0

3 years ago

How does labeling the diagram help us show that we can use right triangle congruency (SAS in this case)?

dem82 [27]

Answer:

Step-by-step explanation:

S A S congruence rule: Two triangles are congruent if two sides and the included angle of one triangle are equal to the two sides and the included angle of other triangle.

If two triangles are congruent by SAS, and the angle is 90, then by CPCT{corresponding part of congruent triangle) the hypotenuse of the two triangles will be congruent.

Now, as hypotenuse and one leg are congruent in both triangles, we can apply RHS congruent

4 0

2 years ago