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Anna11 [10]
3 years ago
12

What does the number of offspring tell us about the number of eggs fertilized?

Biology
2 answers:
Anna35 [415]3 years ago
7 0

Answer:

The number of eggs fertilized in a perfect situation SHOULD be the number of offspring. ... Typically the number of eggs fertilized SHOULD be identical to the number of offspring but is typically leas than the number of eggs fertilized

Explanation:

kolezko [41]3 years ago
6 0

The number of eggs fertilized in a perfect situation SHOULD be the number of offspring. However, outside factors can interfere with the birth of offspring. Typically the number of eggs fertilized SHOULD be identical to the number of offspring but is typically leas than the number of eggs fertilized.

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Prior to the eighteenth century, doctors believed that a person suffering from a chronic illness had an imbalance of body fluids
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Answer:

Peripheral membrane proteins (select one):

D) are generally noncovalently bound to membrane lipids.

Explanation:

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Can someone help me with this question I’m not getting it
RSB [31]

Answer:

a. X^BY

b. X^BX^B

c. X^{b} Y

d. X^BX^b

e. X^bX^b

Explanation:

There are two sex chromosomes, X and Y. A female has two X chromosomes and the male has an X and a Y. The genotype then for male and female woud be:

Female = XX

Male = XY

Now the superscript indicates the allele for a particular trait.

Based on what was given:

H is dominant (no hemophilia)

h is recessive (hemophilic)

B is dominant (no color blindness)

b is recessive (color blind)

As you can see in the given, the Y chromosome has no allele, this means that hemophilia and color-blindness is X-linked or dependent on the X chromosome.

For the first, it says normal male this means that the genotype would be XY , the X chromosome would have the normal dominant allele for color-blindness so that would be B.

X^BY

The next one would be homozygous normal female. This means that the female has both dominant alleles on their chromosome (BB)

X^BX^B

The third one says colorblind male. Unlike the females, the male chromosomes only need the X to be affected for them to express the trait. So in this case, the X will have the recessive allele for colorblindness (b).

X^{b} Y

The foruth one is a normal female for color-blindess but is heterozygous. This means that the female has the recessive allele, but the dominant trait masks it. So it will have both alleles (Bb)

X^BX^b

Lastly, a color-blind female would have to have two recessive alleles. This is what we call homozygous recessive (bb).

X^bX^b

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