Quadrilateral ABCD has coordinates A (3,5), B (5,2), C (8,4), D (6, 7).
2 answers:
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Answer:
h = 452.5 ft
Step-by-step explanation:
Angle of elevation from P to top of the pole = 65°
Horizontal distance between the pole and point P = 21 ft
By Applying tan rule in the given triangle ABP,
tan(∠APB) =
tan(65°) =
h = 21[tan(65°)]
h = 452.491
h ≈ 452.5 ft
Therefore, height of the pole is 452.5 ft.
