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3 years ago

Quadrilateral ABCD has coordinates A (3,5), B (5,2), C (8,4), D (6, 7).

Mathematics

2 answers:

lorasvet [3.4K]3 years ago

7 0

Answer:

square

Step-by-step explanation:

all four sides are congruent and adjacent sides are perpendicular

siniylev [52]3 years ago

4 0

Answer:

B. Square, because all four sides are congruent and adjacent sides are perpendicular

Step-by-step explanation:

A graph of your figure is below.

The figure is a square because

All four sides are congruent
Adjacent sides are perpendicular.

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10.Which of the following values does not satisfy the inequality ?

kupik [55]

Answer:

The answer is -4

Step-by-step explanation:

-2x-6<=1

-2(-4)-6<=1

8-6<=1

2<=1 which is False

-2x-6<=1

-2(-3)-6<=1

6-6<=1

0<=1 which is True

-2x-6<=1

-2(-2)-6<=1

4-6<=1

-2<=1 which is True

-2x-6<=1

-2(-1)-6<=1

2-6<=1

-4<=1 which is True

7 0

3 years ago

Consider a regular hexagon centered at (3,4). Describe a rotation that

Ne4ueva [31]

Answer:

36- degree rotation m8

Step-by-step explanation:

mark me brainliest :)

3 0

3 years ago

Una cámara fotográfica tiene un precio 5200 sin iva ¿cuanto se pagará de iva 16%

Free_Kalibri [48]

Answer:

el tiempo es de 46% caracteres fotográficos ya que si el precio es de 5200 la mitad es 3890

6 0

3 years ago

Given: AD = BC and AD || BC

bearhunter [10]

Answer:

ABCD is a parallelogram.

Step-by-step explanation:

A parallelogram is a quadrilateral that has two parallel and equal pairs of opposite sides.

From the given diagram,

Given: AD = BC and AD || BC, then:

i. AB = DC (both pairs of opposite sides of a parallelogram are congruent)

ii. <ADC = < BCD and < DAB = < CBA

thus, AD || BC and AB || DC (both pairs of opposite sides of a parallelogram are parallel)

iii. < BAC = < DCA (alternate angle property)

iv. Join BD, line AC and BC are the diagonals of the quadrilateral which bisect each other. The two diagonals are at a right angle to each other.

v. <ADC + < BCD + < DAB + < CBA = $360^{0}$ (sum of angles in a quadrilateral equals 4 right angles)

Therefore, ABCD is a parallelogram.

4 0

3 years ago

Consider the functions below. f(x, y, z) = x i − z j + y k r(t) = 4t i + 6t j − t2 k (a) evaluate the line integral c f · dr, wh

fredd [130]

With

$\vec r(t)=4t\,\vec\imath+6t\,\vec\jmath-t^2\,\vec k$

we have

$\mathrm d\vec r=(4\,\vec\imath+6\,\vec\jmath-2t\,\vec k)\,\mathrm dt$

The vector field evaluated over this parameterization is

$\vec f(x,y,z)=\vec f(x(t),y(t),z(t))=4t\,\vec\imath+t^2\,\vec\jmath+6t\,\vec k$

so the line integral is

$\displaystyle\int_{-1}^1(4t\,\vec\imath+t^2\,\vec\jmath+6t\,\vec k)\cdot(4\,\vec\imath+6\,\vec\jmath-2t\,\vec k)\,\mathrm dt$

$=\displaystyle\int_{-1}^1(16t+6t^2-12t^2)\,\mathrm dt=-4$

6 0

3 years ago