121 over 121 is a whole number of 1
Answer:
h(x)=x²+6 and g(x)=8x-5
prove that hg(x)=19
Step-by-step explanation:
step 1: hog(x)=h[g(x)]
step 2: h(8x-5)
step 3: h(8x-5)= (8x-5)²+6
step 4: (8x-5)(8x-5)+6
step 5: 16x² +15x +6
If Dylan owes half as much as he used to that would imply that the 28$ would be divided by two which would be 14$, which means that half of what he owed 28$ would now be 14$.
Answer:
5/12
Step-by-step explanation:
First you add 1/4+2/3.
You need to change the denominator so that they are equal to each other
If you multiply the 1/4 by 3/3 you will get 3/12 which is equal to 1/4
Then you need to do the same to 2/3. This time you need to multiply it by 4/4 to get the same denominator which will be 2/3*4/4=8/12
Then you add 3/12+8/12=11/12. You don't need to add the denominator.
After this you will need to subtract 11/12 and 1/2. This time you need to only change the denominator for 1/2.
You multiply the denominator and numerator by 6/6 to 1/2 and you will get 6/12 then you are going to subtract 11/12-6/12 and you will get 5/12
4.5 is the answer
Divide 49 from both sides
220.5 / 49 = 4.5
