Answer quickly please

.................................................................................................

Lena [83]

Answer:

m<B = 141 degrees

Step-by-step explanation:

This shape is a heptagon meaning its angles should have a sum of 900 degrees.

we are given the degrees and we need to ad them up

148+90+120+129+130+142=749

then we subtract 749 from 900 which looks like

900-749=141

from subtracting 749 from 900 we get 141 hence we get our answer that m<B = 141 degrees

5 0

2 years ago

UAAAAAAAAGAAAAAAGAAAAAAAHG GET OUT OF MY HEAD!!

atroni [7]

pneumonoultramicroscopicsilicovolcanoconiosis

a chronic lung disease caused by the inhalation of fine silicate or quartz dust. More examples. Pneumono refers to the lung.

8 0

3 years ago

-1 80/99 needs to get to a decimal

Free_Kalibri [48]

-1.808080808080808
There u go

4 0

3 years ago

What is the solution to this system of linear equations?

pantera1 [17]

In this question, you're solving the systems of equations.

Solve:

2x + y = 1

3x - y = -6

<em>Since the y's could cancel out, lets solve for x</em>

2x + y = 1

3x - y = -6

-------------------

5x = -5

x = -1

Now, we know that x = -1, lets find y by plugging in -1 to x in any of the equations.

2(-1) + y = 1

-2 + y = 1

<em>Add 2 to both sides</em>

y = 3

This means that your answer would be (-1, 3)

Answer:

(-1, 3)

6 0

3 years ago

Read 2 more answers

An electronics hobbyist has three electronic parts cabinets with two drawers each.

Andrews [41]

Answer:

a) 0.5 = 50% probability that an NPN transistor will be selected.

b) 0.3333 = 33.33% probability that it came from the cabinet that contains both types

c) 66.67% probability that it comes from the cabinet that contains only NPN transistors

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

a) What is the probability that an NPN transistor will be selected?

1/3 probability that the first cabinet is chosen. This cabinet has two transistors, both of which are NPN, so 100% probability of selecting a NPN transistor.

1/3 probability that the second cabinet is chosen. This cabinet has two transistors, both of which are PNP, so 0% probability of selecting a NPN transistor.

1/3 probability that the second cabinet is chosen. This cabinet has two transistors, one of which is NPN, so 50% probability of selecting a NPN transistor.

So

$p = \frac{1}{3}*1 + \frac{1}{3}*0 + \frac{1}{3}*0.5 = \frac{1}{3} + \frac{1}{6} = \frac{2}{6} + \frac{1}{6} = \frac{3}{6} = 0.5$

0.5 = 50% probability that an NPN transistor will be selected.

b) Given that the hobbyist selects an NPN transistor, what is the probability that it came from the cabinet that contains both types?

Here we use the conditional probability formula.

Event A: NPN transistor

Event B: From the third cabinet.

50% probability that an NPN transistor will be selected, so $P(A) = 0.5$ .

1/6 probability that it is from the third cabinet and NPN, so $P(A \cap B) = \frac{1}{6}$

The desired probability is:

$P(B|A) = \frac{\frac{1}{6}}{0.5} = 0.3333$

0.3333 = 33.33% probability that it came from the cabinet that contains both types.

c) Given that an NPN transistor is selected what is the probability that it comes from the cabinet that contains only NPN transistors?

Either it comes from the cabinet with only NPN transistors, or it comes from the cabinet with both types of transistors. The sum of the probabilities of these outcomes is 100%. So

x + 33.33 = 100

x = 66.67

66.67% probability that it comes from the cabinet that contains only NPN transistors

6 0

3 years ago