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KonstantinChe [14]
3 years ago
13

How do you find the value of x in. x+y=z

Mathematics
1 answer:
fomenos3 years ago
7 0
You would subtract y on both sides so z-y then you get x=x. I think I hope this helps.
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"Find the sum of the first 50 term in this sequence 4, 7, 10, 13, ...". How do i do this without writing them all out, and how d
melisa1 [442]
First term ,a=4 , common difference =4-7=-3, n =50
sum of first 50terms= (50/2)[2×4+(50-1)(-3)]
=25×[8+49]×-3
=25×57×-3
=25× -171
= -42925
derivation of the formula for the sum of n terms
Progression, S
S=a1+a2+a3+a4+...+an

S=a1+(a1+d)+(a1+2d)+(a1+3d)+...+[a1+(n−1)d]   →   Equation (1)

S=an+an−1+an−2+an−3+...+a1

S=an+(an−d)+(an−2d)+(an−3d)+...+[an−(n−1)d]   →   Equation (2)

Add Equations (1) and (2)
2S=(a1+an)+(a1+an)+(a1+an)+(a1+an)+...+(a1+an)

2S=n(a1+an)
S=n/2(a1+an)

Substitute an = a1 + (n - 1)d to the above equation, we have
S=n/2{a1+[a1+(n−1)d]}
S=n/2[2a1+(n−1)d]
5 0
3 years ago
Explain the difference between correlation and causation and what makes causation difficulty to prove?
bixtya [17]
Ausation<span> vs. </span>Correlation<span>. </span>Causation<span> at its simplest definition refers to determining the cause or reason for some sort of phenomenon. ... A </span>correlation<span> is simply a recognized </span>relationship between<span> two things or events, but it does not imply</span>causation<span>. Rather, in cases of </span>correlation<span>, one thing or event predicts another. hope it helps</span>
6 0
3 years ago
Help pls will give brainlist make sure to show work if needed
weqwewe [10]

Answer:

11

Step-by-step explanation:

Just make your dot plot so that the amount of dots corresponding to the number is the amount of times the number shows in the box. :)

4 0
3 years ago
The prior probabilities for events A1 and A2 are P(A1) = 0.35 and P(A2) = 0.50. It is also known that P(A1 ∩ A2) = 0. Suppose P(
forsale [732]

Answer:

Step-by-step explanation:

Hello!

Given the probabilities:

P(A₁)= 0.35

P(A₂)= 0.50

P(A₁∩A₂)= 0

P(BIA₁)= 0.20

P(BIA₂)= 0.05

a)

Two events are mutually exclusive when the occurrence of one of them prevents the occurrence of the other in one repetition of the trial, this means that both events cannot occur at the same time and therefore they'll intersection is void (and its probability zero)

Considering that P(A₁∩A₂)= 0, we can assume that both events are mutually exclusive.

b)

Considering that P(BIA)= \frac{P(AnB)}{P(A)} you can clear the intersection from the formula P(AnB)= P(B/A)*P(A) and apply it for the given events:

P(A_1nB)= P(B/A_1) * P(A_1)= 0.20*0.35= 0.07

P(A_2nB)= P(B/A_2)*P(A_2)= 0.05*0.50= 0.025

c)

The probability of "B" is marginal, to calculate it you have to add all intersections where it occurs:

P(B)= (A₁∩B) + P(A₂∩B)=  0.07 + 0.025= 0.095

d)

The Bayes' theorem states that:

P(Ai/B)= \frac{P(B/Ai)*P(A)}{P(B)}

Then:

P(A_1/B)= \frac{P(B/A_1)*P(A_1)}{P(B)}= \frac{0.20*0.35}{0.095}= 0.737 = 0.74

P(A_2/B)= \frac{P(B/A_2)*P(A_2)}{P(B)} = \frac{0.05*0.50}{0.095} = 0.26

I hope it helps!

5 0
3 years ago
The following problem describes procedures that are to be applied to numbers. Repeat the procedure for four numbers of your choi
mart [117]

Answer:

Conjecture: For every number x, the result of the is 2x

Step-by-step explanation:

First Number: 8

Multiply by 88: 88 * 8 = 704

Add 88: 704 + 88 = 792

Divide by 44: 792/44 = 18

Subtract 2: 18 - 2 = 16

Second: 10

Multiply by 88: 88 * 10 = 880

Add 88: 880+88=968

Divide by 44: 968/44=22

Subtract 2: 22-2=20

Third: 5

Multiply by 88: 88*5 = 440

Add 88: 440+88=528

Divide by 44: 528/44=12

Subtract 2: 12-2=10

Fourth: 2

Multiply by 88: 88*2=176

Add 88: 176+88=264

Divide by 44: 264/44=6

Subtract 2: 6-2=4

On a general terms:

Let the number be x.

Multiply by 88: 88x

Add 88: 88x + 88

Divide by 44: \frac{88x + 88}{44} = \frac{88x}{44} + \frac{88}{44} = 2x+2

Subtract 2: 2x + 2 - 2 = 2x

Notice that for every input x, the result is 2x

8 0
3 years ago
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