Answer: dude you can do this yourself.
Step-by-step explanation:
toss coins ;-;
Answer:
- There is no significant evidence that p1 is different than p2 at 0.01 significance level.
- 99% confidence interval for p1-p2 is -0.171 ±0.237 that is (−0.408, 0.066)
Step-by-step explanation:
Let p1 be the proportion of the common attribute in population1
And p2 be the proportion of the same common attribute in population2
: p1-p2=0
: p1-p2≠0
Test statistic can be found using the equation:
where
- p1 is the sample proportion of the common attribute in population1 (
)
- p2 is the sample proportion of the common attribute in population2 (
)
- p is the pool proportion of p1 and p2 (
)
- n1 is the sample size of the people from population1 (30)
- n2 is the sample size of the people from population2 (1900)
Then
≈ 2.03
p-value of the test statistic is 0.042>0.01, therefore we fail to reject the null hypothesis. There is no significant evidence that p1 is different than p2.
99% confidence interval estimate for p1-p2 can be calculated using the equation
p1-p2±
where
- z is the z-statistic for the 99% confidence (2.58)
Thus 99% confidence interval is
0.533-0.704±
≈ -0.171 ±0.237 that is (−0.408, 0.066)
35 50 65 I have to type more because it doesn’t let me answer if I don’t
Answer: 0.15km/min and 0.3km in 2 mins
Step-by-step explanation:
Given Data:
Cyclists speed = 9km/hr
1. Some traveling 60 km/h is traveling one km/min
60/60= 1 km/min
Rate in km/min
= 9km/hr / 60min
= 3/20 km/min
= 0.15 km/min
Kilometers travelled in 2mins
= 2 / 60
= 1 / 30
= 9km/hr * 1 / 30
= 9 / 30
= 0.3 km in 2mins