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krek1111 [17]
2 years ago
13

20 points pleas help!!

Mathematics
2 answers:
Anna [14]2 years ago
5 0

I think if I did it right it should be B

liq [111]2 years ago
3 0
The answer should be c
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Describe the steps on how to graph the ordered pair ( - 3, 4)​
larisa [96]

Answer:

find -3 on the graph on the left side. and go four up from there

Step-by-step explanation:

6 0
3 years ago
What is 4 + 1 <br> cause i'm stuck on this question hehe
s2008m [1.1K]
Tis’ 5 mah lad

Explernation:

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6 0
2 years ago
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Which equation represents a line that passes through (-9,-3) and has a slope of -6?
zmey [24]

Answer: y=-6x-57

Step-by-step explanation: the normal format of a linear equation is

y=(slope)x+y intercept. The slope is -6 so y=-6x+y intercept. Plugging in the cordinates, -3=-9(-6)+y intercept. We'll call the y intercept b. -3=54+b. Subtract 54 from both sides of the equation and you get b=-54. The linear equation is

y=-6x-57.

You can check by plugging in x= -9, and y= -3. -3=54-57. -3=-3

4 0
3 years ago
JL is a common tangent to circles M and K at point J. If angle MLK measures 61ᵒ, what is the length of radius MJ? Round to the n
Sladkaya [172]
3.122

The process to getting this comes in many steps. Firstly, you need to find the angles for JLK and MLJ. To find JLK use the arcsin function using the opposite side and the hypotenuse. 

Arcsin(Opp/Hype) = JLK
Arcsin(.5) = JLK
30 degrees = JLK

This means MLJ = 31 degrees since they add up to 61 degrees. 

Now we need to find the length of LJ, which we can do using the Pythagorean Theorem. 

3^2 + JL^2 = 6^2
9 + JL^2 = 36
JL^2 = 27
JL = \sqrt{27}

Now that we have the angle of MLJ and the length of JL, we can use the tangent function to find MJ.

Tan(angle) = opp/adj
Tan(31) = MJ/\sqrt{27}
\sqrt{27}Tan(31) = MJ
3.122 = MJ
7 0
4 years ago
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Today Harvey ran 2km more than twice as far as he ran yesterday. Let y= the number of kilometers he ran yesterday. Write an expr
KatRina [158]

The answer is y=2x+2.

8 0
3 years ago
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