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Brums [2.3K]
3 years ago
14

A distributor of personal computers has five locations in a city. In the year's first quarter, the sales in units were: Location

Observed Sale ( units) Northside 70 Pleasant Township 75 Southwick 70 I-90 50 Venice Avenue 35 Total 300 For a goodness-of-fit test that sales were the same for all locations, what is the critical value at the 0.01 level of risk? Select one: a. 7.779 b. 15.033 c. 13.277 d. 5.412

Mathematics
1 answer:
Deffense [45]3 years ago
7 0

Answer:

The correct option is (c) 13.277.

Step-by-step explanation:

The observed data is:

Location                      Observed sales (units)

Northside                                70

Pleasant Township                 75

Southwick                               70

I-90                                          50

Venice Avenue                       35

TOTAL                                   300

The test statistic for the Goodness of fit test is:

\chi^{2}=\sum\frac{(Observed-Expected)^{2}}{Expected}

For <em>k</em> independent samples this test statistic follows a Chi-square distribution with degrees of freedom (<em>k</em> - 1).

The sample size in this case is, <em>k</em> = 5.

The degrees of freedom is, (<em>k</em> - 1) = 4.

The level of significance is, <em>α</em> = 0.01.

The critical value of the test is:

\chi^{2}_{\alpha ,k-1}=\chi^{2}_{0.01,4}=13.277

**Use the Chi-square table.

Thus, the critical value is 13.277.

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4 years ago
A box of chocolates contains 18 chocolate squares, tens of the square are milk chocolate, 5 are dark chocolate, and 3 are.white
Step2247 [10]

Answer:

0.167 ; 0.093

Step-by-step explanation:

Given that:

Total number of chocolate squares = 18 of which÷

Number of milk chocolate square = 10

Dark chocolate square = 5

White chocolate square= 3

Probability of choosing a white chocolate square :

Probability = required outcome / Total possible outcomes

Required outcome = white chocolate square = 3

Number of chocolate square = 18

P(choosing a white chocolate square) = 3 / 18 = 1/6 =

B) probability of randomly selecting a milk chocolate first, replace it, and then select a white chocolate?

With replacement :

First pick :

Number milk chocolate = 10

P(choosing a milk chocolate) = 10/18 = 5/9

Second pick:

Number of white chocolate = 3

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Hence, since both probabilities are independent :

P(choosing milk, then white chocolate) :

(5/9 × 1/6) = 5/54 = 0.0925 = 0.093

8 0
3 years ago
Polynomial of degree 4 has 1 positive real root that is bouncer and 1 negative real root that is a bouncer. How many imaginary r
Rainbow [258]

Answer:

<h3>The given polynomial of degree 4 has atleast one imaginary root</h3>

Step-by-step explanation:

Given that " Polynomial of degree 4 has 1 positive real root that is bouncer and 1 negative real root that is a bouncer:

<h3>To find how many imaginary roots does the polynomial have :</h3>
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  • Therefore it must have four roots.
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<h3>Hence the given polynomial of degree 4 has atleast one imaginary root</h3><h3> </h3>

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katen-ka-za [31]
The answer to this would be O
5 0
3 years ago
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PLZZ HELP I NEED AN EXPERT ANSWER
Sav [38]
The equation of a line is y = mx + b


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