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laiz [17]
2 years ago
11

As part of each science lab, Mr. Arico requires his student to wash their glassware, so it is clean for the next class. He has f

ound that the glassware is cleaner when students wash it in front of their classmates. This is best explained by
social facilitation
deindividuation
social loafing
the mere exposure effect
groupthink
Chemistry
1 answer:
FinnZ [79.3K]2 years ago
5 0

Answer:

social facilitation

Explanation:

You might be interested in
2. A block of material has a volume of 2 m3. It has a mass of 1 × 104 kg. Calculate the density of the material sample and expre
maks197457 [2]
Density = mass / volume

D = 1 x 10⁴ / 2

D = 5000 kg/m³ in g/cm³:

1 kg/m³ ---------------- 0.001 g/cm³
5000 kg/m³ ----------- ??

5000 x 0.001 / 1 =>  5.0 g/cm³

hope this helps!
7 0
3 years ago
Convert the following temperature to c 67k b) 1671k
kap26 [50]
  • Convert Kelvin to °c

(a) 67°c

Formula:-

k=°c+273

°c = 273 - k

°c = 273-67= 206 °c

(b) 1671 k

k=°c+273

°c = 273 - k

°c= 273-1671 = -1398°c

8 0
2 years ago
Which is a balanced chemical equation?
Degger [83]
<h3>Answer:</h3>

B. C7H16 + 11O2 → 7CO2 + 8H2O

<h3>Explanation:</h3>
  • In a balanced chemical equation, the number of atoms of each element is equal on both sides of the equation.
  • In this case, the balanced chemical equation is;

   C7H16 + 11O2 → 7CO2 + 8H2O

Because, it has 7 carbon atoms, 16 hydrogen atoms and 22 oxygen atoms on each side of the equation.

  • When an equation is balanced it obeys the law of conservation of mass such that the mass of reactants will be equal to the mass of products.
8 0
3 years ago
Find the density of a cube on Earth that weighs 1.5 kg and has a side-length of 10 cm.
Inga [223]

Answer:

1.5g/cm³

Explanation:

density=mass÷volume

mass= 1.5kg (<em>c</em><em>h</em><em>a</em><em>n</em><em>g</em><em>e</em><em> </em><em>i</em><em>n</em><em>t</em><em>o</em><em> </em><em>g</em>) = 1500g

volume of the cube = 10×10×10 = 1000cm³

density= divide 1500g÷1000cm = 1.5g/cm³

<h2>Density= 1.5g/cm³</h2>

YOUR WELCOME!

4 0
3 years ago
A sample of 28 Mg decays initially at a rate of 53500 disintegrations per minute, but the decay rate falls to 10980 disintegrati
prisoha [69]

Answer : The half life of 28-Mg in hours is, 6.94

Explanation :

First we have to calculate the rate constant.

Expression for rate law for first order kinetics is given by:

k=\frac{2.303}{t}\log\frac{a}{a-x}

where,

k = rate constant

t = time passed by the sample = 48.0 hr

a = initial amount of the reactant disintegrate = 53500

a - x = amount left after decay process disintegrate = 53500 - 10980 = 42520

Now put all the given values in above equation, we get

k=\frac{2.303}{48.0}\log\frac{53500}{42520}

k=9.98\times 10^{-2}hr^{-1}

Now we have to calculate the half-life.

k=\frac{0.693}{t_{1/2}}

9.98\times 10^{-2}=\frac{0.693}{t_{1/2}}

t_{1/2}=6.94hr

Therefore, the half life of 28-Mg in hours is, 6.94

8 0
3 years ago
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