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riadik2000 [5.3K]

3 years ago

11

How is the mass of 1 mole of an element determined

1 answer:

Tatiana [17]3 years ago

3 0

One mole (abbreviated mol) is equal to 6.022×1023 molecular entities (Avogadro's number), and each element has a different molar mass depending on the weight of 6.022×1023 of its atoms (1 mole). The molar mass of any element can be determined by finding the atomic mass of the element on the periodic table.

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Use the de Broglie's Wave Equation to find the wavelength of an electron moving at 7.3 × 106 m/s. Please show your work. Note: h

ad-work [718]

Answer:

$\lambda=9.96\times 10^{-11}\ m$

Explanation:

The expression for the deBroglie wavelength is:

$\lambda=\frac {h}{m\times v}$

Where,

$\lambda$ is the deBroglie wavelength

h is Planck's constant having value $6.62607\times 10^{-34}\ Js$

m is the mass of electron having value $9.11\times 10^{-31}\ kg$

v is the speed of electron.

Given that v = $7.3\times 10^6\ m/s$

Applying in the equation as:

$\lambda=\frac {h}{m\times v}$

$\lambda=\frac{6.62607\times 10^{-34}}{9.11\times 10^{-31}\times 7.3\times 10^6}\ m$

$\lambda=\frac{10^{-34}\times \:6.626}{10^{-25}\times \:66.503}\ m$

$\lambda=\frac{6.626}{10^9\times \:66.503}\ m$

$\lambda=9.96\times 10^{-11}\ m$

6 0

3 years ago

What type of energy travels in the form of electromagnetic waves?

almond37 [142]

Light/thermal. Charges move back and forth which move at the speed of light

3 0

3 years ago

A piece of metal with a mass of 159 g is placed in a 50 mL graduated cylinder. The water level rises from 20. mL to 41 mL. What

almond37 [142]

Volume of water displaced is equal to the volume of the metal. So 41 - 20 = 21 ml. Density = mass / volume so density = 159 / 21 = 7.57 g/ml

8 0

3 years ago

A gravel can be broken down into different kinds of substances by physical processes. No chemical reactions are needed to separa

butalik [34]

answer:

heterogenous mixture

Explanation:

6 0

2 years ago

Read 2 more answers

18 g of copper is mixed with silver nitrate in water. How much copper ll nitrate will formed?

Lorico [155]

Answer:

Mass = 112.54 g

Explanation:

Given data:

Mass of copper = 18 g

How much copper(II) nitrate formed = ?

Solution:

Cu + 2AgNO₃ → Cu(NO₃)₂ + 2Ag

Number of moles of copper:

Number of moles = mass/ molar mass

Number of moles = 18 g/ 29 g/mol

Number of moles = 0.6 mol

Now we will compare the moles of Cu with Cu(NO₃)₂ .

Cu : Cu(NO₃)₂

1 : 1

0.6 : 0.6

Mass of Cu(NO₃)₂ :

Mass = number of moles × molar mass

Mass = 0.6 mol × 187.56 g/mol

Mass = 112.54 g

7 0

3 years ago