Answer:
1281.25 Moles of glucose
Explanation:
Multiply 1.25x1025= 1281.25
Answer:

Explanation:
Hello there!
In this case, given the solubilization of cadmium (II) hydroxide:

The solubility product can be set up as follows:
![Ksp=[Cd^{2+}][OH^-]^2](https://tex.z-dn.net/?f=Ksp%3D%5BCd%5E%7B2%2B%7D%5D%5BOH%5E-%5D%5E2)
Now, since we know the concentration of cadmium (II) ions at equilibrium and the mole ratio of these ions to the hydroxide ions is 1:2, we infer that the concentration of the latter at equilibrium is 3.5x10⁻⁵ M. In such a way, the resulting Ksp turns out to be:

Regards!
Answer:
last one is the correct and most suitable option.
Hope it helps!!!
The correct answer is D - When burning a log, the wood combined its components with oxygen. if you could capture the products (CO2, H2O, C, CO, etc), you would have a greater mass than what you started with, burning the log combined the log's components with oxygen in order to burn it.