Answer:
D) 2, 4, and 5
Explanation:
In order to fully comprehend the answer choices we must take a close look at the value of ΔH° = 31.05. The enthalpy change of the reaction is positive. A positive value of enthalpy of reaction implies that heat was absorbed in the course of the reaction.
If heat is absorbed in a reaction, that reaction is endothermic.
Since ∆Hreaction= ∆H products -∆H reactants, a positive value of ∆Hreaction implies that ∆Hproducts >∆Hreactants, hence the answer choice above.
The molarity of HCL is 71mL, the H3O+ 49g, and the pH is 12.
Answer:
C. 0.191 M
Explanation:
Our goal for this question, is to calculate the concentration of the HCl solution. For this, in the experiment, a solution of NaOH was used to find the moles of HCl. Therefore, our first step is to know the <u>reaction between HCl and NaOH</u>:

The "<u>titrant"</u> in this case is the NaOH solution. If we know the concentration of NaOH (0.100M) and the volume of NaOH (38.2 mL=0.0382 L), we can calculate the moles using the <u>molarity equation</u>:



Now, in the reaction, we have a <u>1:1 molar ratio</u> between HCl and NaOH (1 mol of HCl is consumed for each mole of NaOH added). Therefore we will have the same amount of moles of HCl in the solution:

If we want to calculate the molarity of the HCl solution we have to <u>divide by the litters</u> of HCl used in the experiment (20 mL= 0.02 L):

The concentration of the HCl solution is 0.191 M
I hope it helps!
Environmental consultant.
Environmental education officer.
Environmental engineer.
Answer:
conductors of electricity when in liquid or aqueous state
high melting point
soluble in water
Explanation:
An ionic substance is any substance that is composed of two ions of opposite charge.
In the solid state, ionic substances do not conduct electricity because the ions are trapped inside the crystal. When in liquid state or in aqueous solution, these ions are now free and the solution becomes an electrolyte.
All ionic substances have a very high melting point and dissolve in water easily.