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3 years ago

State the domain and range of f(x)=[[x-2]]

Mathematics

1 answer:

noname [10]3 years ago

8 0

Answer:

domain: -infinity < x <infinity or (-infinity, infinity)

range: -infinity < f(x) < infinity or (-infinity, infinity)

Step-by-step explanation:

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larisa86 [58]

Answer:

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Step-by-step explanation:

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3 years ago

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Can someone please help me solve for X i’m really confused and I really need help please

DochEvi [55]

Answer: x = 7

Step-by-step explanation:

sure thing! so, one angle is 34 degrees, and the other clear angle is 60 degrees. we know that because the angle on the lower shape matches that one. we then just add those, which comes out to 94 degrees. a triangle is 180 degrees, so we subtract 94 from that in order to figure out the total degrees in that last angle. that angle comes out to be 86 degrees. then, we subtract 2 in order to divide easily. we then divide 84 by 12, and we get 7. so, x = 7

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3 years ago

3.9x - 0.7 = 8.66, so what does x equal?

scoundrel [369]

Answer:

x=2.4

Step-by-step explanation:

brainliest pls

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2 years ago

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Consider a discrete random variable x with pmf px (1) = c 3 ; px (2) = c 6 ; px (5) = c 3 and 0 otherwise, where c is a positive

PtichkaEL [24]

Looks like the PMF is supposed to be

$\mathbb P(X=x)=\begin{cases}\dfrac c3&\text{for }x\in\{1,5\}\\\\\dfrac c6&\text{for }x=2\\\\0&\text{otherwise}\end{cases}$

which is kinda weird, but it's not entirely clear what you meant...

Anyway, assuming the PMF above, for this to be a valid PMF, we need the probabilities of all events to sum to 1:

$\displaystyle\sum_{x\in\{1,2,5\}}\mathbb P(X=x)=\dfrac c3+\dfrac c6+\dfrac c3=\dfrac{5c}6=1\implies c=\dfrac65$

Next,

$\mathbb P(X>2)=\mathbb P(X=5)=\dfrac c3=\dfrac25$

$\mathbb E(X)=\displaystyle\sum_{x\in\{1,2,5\}}x\,\mathbb P(X=x)=\dfrac c3+\dfrac{2c}6+\dfrac{5c}3=\dfrac{7c}3=\dfrac{14}5$

$\mathbb V(X)=\mathbb E\bigg((X-\mathbb E(X))^2\bigg)=\mathbb E(X^2)-\mathbb E(X)^2$
$\mathbb E(X^2)=\displaystyle\sum_{x\in\{1,2,5\}}x^2\,\mathbb P(X=x)=\dfrac c3+\dfrac{4c}6+\dfrac{25c}3=\dfrac{28c}3=\dfrac{56}5$
$\implies\mathbb V(X)=\dfrac{56}5-\left(\dfrac{14}5\right)^2=\dfrac{84}{25}$

If $Y=X^2+1$ , then $X^2=Y-1\implies X=\sqrt{Y-1}$ , where we take the positive root because we know $X$ can only take on positive values, namely 1, 2, and 5. Correspondingly, we know that $Y$ can take on the values $1^2+1=2$ , $2^2+1=5$ , and $5^2+1=26$ . At these values of $Y$ , we would have the same probability as we did for the respective value of $X$ . That is,

$\mathbb P(Y=y)=\begin{cases}\dfrac c3&\text{for }y=2\\\\\dfrac c6&\text{for }y=5\\\\\dfrac c3&\text{for }y=26\\\\0&\text{otherwise}\end{cases}$

Part (5) is incomplete, so I'll stop here.

8 0

3 years ago

I REALLY NEED HELP, ILL MEDAL!!!!

lara31 [8.8K]

Well, first of all, the first statement (ABC = ADC) looks like it just says
that the two halves of the little square ... each side of the diagonal ...
are congruent. That's no big deal, and it's no help in answering the
question.

The effect of the dilation is that all the DIMENSIONS of the square
are doubled ... each side of the square becomes twice as long.

Then, when you multiply (length x width) to get the area, you'd have

Area = (2 x original length) x (2 x original width)

and that's
the same as (2 x 2) x (original length x original width)

= (4) x (original area) .

Here's an easy, useful factoid to memorize:

-- Dilate a line (1 dimension) by 'x' times . . . multiply the length by x¹

-- Dilate a shape (2 dimensions) by 'x' . . . multiply area by x²

-- Dilate a solid (3 dimensions) by 'x' . . . multiply volume by x³

And that's all the dimensions we have in our world.
_______________________________

Oh, BTW . . .

-- Dilate a point (0 dimensions) by 'x' . . . multiply it by x⁰ (1)

5 0

3 years ago