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Pachacha [2.7K]
3 years ago
12

Calculate the surface area of the rectangular prism to the tenth of a square centimetre

Mathematics
1 answer:
kumpel [21]3 years ago
7 0

Answer:

A=152.32 cm^2

Step-by-step explanation:

A=2(wl+hl+hw)

A=2(6.8*3.4+5.2*3.4+5.2*6.8)

A=2(23.12+17.68+35.36)

A=2(76.16)

A=152.32

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Answer:

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#3 Can someone please help me with these questions!!!!
rosijanka [135]

Answer:

Option A 90,68

m\angle 1=90^o

m\angle 2=68^o

Step-by-step explanation:

see the attached figure to better understand the problem

The figure shows a kite

we know that

A kite properties include

1) two pairs of consecutive, congruent sides

2) congruent non-vertex angles

3) perpendicular diagonals

Find the measure of angle 1

we have that

m\angle 1=90^o ----> by the diagonals are perpendicular

Find the measure of angle 2

we know that

triangle AEB is congruent with triangle CEB

so

m\angle EAB=m\angle ECB=m\angle 2

In the right triangle EAB

m\angle EAB+22^o=90^o ----> by complementary angles in a right triangle

so

m\angle EAB=90^o-22^o=68^o

therefore

m\angle 2=68^o

7 0
3 years ago
Yellow Cab Taxi charges a $1.75 flat rate in addition to $0.65 per mile. Katie has no more than $10 to spend on a ride. How many
spayn [35]
About  miles. 

Subtract the flat rate of 1.75 from the spending limit of 10$ which leaves you with 8.25 then divide the rest of your spending money (8.25$) into your rate per mile (0.65) , so essentially , 8.25 / 0.65 which leaves you with the answer of ;
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Read 2 more answers
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3 years ago
A small junior college had an enrollment of 7,843 students in the year 1990 and 8,793 students in the year 2000. Let x=0 represe
abruzzese [7]

Correct answer is: (0,7843) and (10,8793)

Solution:-

Given that a junior college has an enrollment of 7843 students in 1990 and 8793 students in year 2000.

We have to write this data as (x,y) .

Where x= years after 1990 and y=number of students enrolled.

Since in 1990, 7843 students enrolled, x = 1990-1990=0

And y=7843.

Hence one ordered pair is (0,7843).

Let us find the years after 1990 for 2000 = 2000-1990 =10

Hence another ordered pair is (10,8793).

4 0
4 years ago
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