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vampirchik [111]
3 years ago
11

Find the volume of a pyramid with a square base, where the side length of the base is 8 . 3 8.3 ft and the height of the pyramid

is 1 2 . 3 12.3 ft. Round your answer to the nearest tenth of a cubic foot.
Mathematics
1 answer:
seraphim [82]3 years ago
4 0
Where A is the area of the base and h is the height of the pyramid. Volume of a Square- based Pyramid. The volume of a square- based pyramid is given by. Example 39
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What is the surface area of a rectangular prism with a length of 3 mm, a width of 5 mm, and a height of 8 mm?
kherson [118]
158, because to solve this question we first need to know the formula for finding the surface area of a rectangular prism which is A=<span>2<span>(<span><span><span>wl</span>+<span>hl</span></span>+<span>hw</span></span><span>) then you just need to input the numbers like so A=2(5*3+8*3+8*5) then when you simplify this down you get A=2(79) then distribute like so so A=158

Enjoy!=)</span></span></span>
8 0
3 years ago
The actual depth of a lake is 15.8 meters.
Anna35 [415]

Answer:

0.2 meters

Step-by-step explanation:

16-15.8 is 0.2 haha

8 0
3 years ago
(-4,-6) and (3,-7) find the distance between each pair of points
Vlad [161]

Answer:

5\sqrt{2}

Step-by-step explanation:

distance between two points:

d = \sqrt{(x_{2}-x_{1})^{2}+ (y_{2}-y_{1})^{2}}

we have:

(-4, -6), (3, -7)

x_{1} = -4

y_{1} =-6

x_{2} = 3

y_{2} =-7

so we have:

d =\sqrt{(3-(-4))^{2}+ (-7-(-6))^{2}}\\\\d =\sqrt{(7)^{2}+ (-1)^{2}}\\\\d = \sqrt{49+ 1}\\\\d=\sqrt{50}\\\\d=5\sqrt{2}

4 0
3 years ago
Read 2 more answers
PLEASE HELP I NEED HELP
bulgar [2K]
Yes because each x value differ by 2.5 and each y value also differs at aconstant rat of 1
3 0
3 years ago
Find the inverse f(x)=6x+7
Lorico [155]

Answer:

f^{-1} (x) = \frac{x-7}{6}

Step-by-step explanation:

let y = f(x) , then rearrange making x the subject

y = 6x + 7 ( subtract 7 from both sides )

y - 7 = 6x ( divide both sides by 6 )

\frac{y-7}{6} = x

Change y back into terms of x with x = f^{-1} (x) , then

f^{-1} (x) = \frac{x-7}{6}

7 0
3 years ago
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