Answer:
Let's choose the three odd consecutive numbers 1, 3, and 5.
3^2=9
1•5=5
9-5=4
Let's try the same thing, but with the numbers 101, 103, and 105.
103^2=10609
101•105=10605
10609-10605=4
So, yes, the square of the second number out of three consecutive odd numbers is four greater than the product of the first and the third numbers.
Answer:
x=47
Step-by-step explanation:
Let's solve your equation step-by-step.
180=x+3x−8
Step 1: Simplify both sides of the equation.
180=x+3x−8
180=x+3x+−8
180=(x+3x)+(−8)(Combine Like Terms)
180=4x+−8
180=4x−8
Step 2: Flip the equation.
4x−8=180
Step 3: Add 8 to both sides.
4x−8+8=180+8
4x=188
Step 4: Divide both sides by 4.
4x4=1884
x=47
Answer:
67.
Step-by-step explanation:
First we find the mean:
Mean is add up everything and divide by how much numbers there are.
The numbers are:
.
So we add them up which is 536.
Then we divide by how much numbers there are.
There are 8 numbers so 536/8 which is 67.
Hope this helps :D
Y + 3 = 1.2(x - 0)
y + 3 = 1.2x - 0
y = 1.2x - 3
<span>(3x^2+3)(4+x^3)
=</span><span>12x^2 +3x^5 + 12 + 3x^3
= </span>3x^5 + 3x^3 + 12x^2 + 12
