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3 years ago

Help help......................................................................................

Mathematics

1 answer:

fenix001 [56]3 years ago

6 0

Hey there! Is there more text to this? I would love to help, but there is no question.

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How do you find the midpoint M?

posledela

Answer:

Step-by-step explanation

By using midpoint formula :

(X,Y) = (X1+X2/2) ,(Y1+Y2/2)

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3 years ago

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Please help me!!!!!!!!!

lara [203]

Answer:

The answer to your question is:

Domain [0, 8)

Range [-3, 1]

f(0) = -3

Step-by-step explanation:

Domain: is the possible values that the "x" can take

Range: are the values that take the function when is evaluated by the independent variable (x).

For this example:

Domain [0, 8) close is zero and open in 8

Range [-3, 1] close in both sides

f(0) = -3

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3 years ago

Which<br> expression is equivalent to -3-4

Bess [88]

Answer: wheres the photo ?

Step-by-step explanation:

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3 years ago

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when 6 is subtracted from the square of a number, the result is 5 times the number. Find the negative solution.

sveta [45]

When 6 is subtracted from the square of a number, the result is 5 times the number, then the negative solution is -1

<h3><u>Solution:</u></h3>

Given that when 6 is subtracted from the square of a number, the result is 5 times the number

To find: negative solution

Let "a" be the unknown number

Let us analyse the given sentence

square of a number = $a^2$

6 is subtracted from the square of a number = $a^2 - 6$

5 times the number = $5 \times a$

<em><u>So we can frame a equation as:</u></em>

6 is subtracted from the square of a number = 5 times the number

$a^2 - 6 = 5 \times a\\\\a^2 -6 -5a = 0\\\\a^2 -5a -6 = 0$

<em><u>Let us solve the above quadratic equation</u></em>

For a quadratic equation $ax^2 + bx + c = 0$ where $a \neq 0$

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Here in this problem,

$a^2-5 a-6=0 \text { we have } a=1 \text { and } b=-5 \text { and } c=-6$

Substituting the values in above quadratic formula, we get

$\begin{array}{l}{a=\frac{-(-5) \pm \sqrt{(-5)^{2}-4(1)(-6)}}{2 \times 1}} \\\\ {a=\frac{5 \pm \sqrt{25+16}}{2}=\frac{5 \pm \sqrt{49}}{2}} \\\\ {a=\frac{5 \pm 7}{2}}\end{array}$

We have two solutions for "a"

$\begin{array}{l}{a=\frac{5+7}{2} \text { and } a=\frac{5-7}{2}} \\\\ {a=\frac{12}{2} \text { and } a=\frac{-2}{2}}\end{array}$

We have asked negative solution. So a = -1

Thus the negative solution is -1

6 0

3 years ago

Ryan estimates the measurements of the volume of a container to be 36 cubic inches. the actual volume of the popcorn container i

vlada-n [284]

The absolute error is 4 cubic inches. To find the absolute error, you simply subtract the two values.

The percent error is 10%. To find the percent error, we create a fraction out of the error and the actual value.
4 / 40 x 100 = 10%

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3 years ago