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Anika [276]
3 years ago
14

Four times the larger of two consecutive even integers is ten less than the smaller. What is the larger of these two numbers?

Mathematics
1 answer:
anygoal [31]3 years ago
7 0

Answer:

-4 is the larger integer

Step-by-step explanation:

n = smaller integer

n + 2 = larger integer

4(n+2) = n-10

4n + 8 =  n - 10

3n + 8 = -10

3n = -18

n = -6

n+2 = -4

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Answer:

The exact answer in terms of radicals is x = 5*\sqrt[3]{25}

The approximate answer is x \approx 14.62009 (accurate to 5 decimal places)

===============================================

Work Shown:

Let y = \sqrt[5]{x^3}

So the equation reduces to  -7  = 8-3y

Let's solve for y

-7 = 8-3y

8-3y = -7

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y = -15/(-3) ... divide both sides by -3

y = 5

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Since y = \sqrt[5]{x^3} and y = 5, this means we can equate the two expressions and solve for x

y = 5

\sqrt[5]{x^3} = 5

x^3 = 5^5 Raise both sides to the 5th power

x^3 = 3125

x = \sqrt[3]{3125} Apply cube root to both sides

x = \sqrt[3]{125*25}

x = \sqrt[3]{125}*\sqrt[3]{25}

x = \sqrt[3]{5^3}*\sqrt[3]{25}

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4 0
3 years ago
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Acellus
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Answer:

d = 14

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I need help with this question. Please thanks
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Answer:

all you need to do is to multiple

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