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2 years ago

Emma wants to drive forward in her car. What does she need to do other than place her vehicle's gear in Drive and accelerate

1 answer:

4 0

She need to release the cluch slowly and apply force on the accelator other than place her vehicle's gear in Drive and accelerate

<h3>How we drive a car?</h3>

We drive a car by applying pressure on the accelator, remove foot from the brakes and releasing cluch slowly. When the vehicle get speed, we have to change the gear.

So we can conclude that She need to release the cluch slowly and apply force on the accelator for driving a car.

Learn more about accelaration here: brainly.com/question/605631

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A book is launched up along the rough incline. Kinetic energy given to a book at initial point is 100 J. Book comes to stop at s

den301095 [7]

Answer:

(A) 60 J

Explanation:

At state 1

KE₁=100 J

At state 2

KE₂ = 0

U₂=80 J

Given that surface is rough so friction force will act in opposite to the direction of motion

Lets take work done by friction = Wfr

From work power energy

Work done by all forces = Change in kinetic energy

Wfr + U₂=ΔKE

Wfr+80 = 100

Wfr= 20 J

Now when book slides from top position then

Wfr+ U = KEf - KEi

-20 + 80 = KEf-0

KEf= 60 J

(A) 60 J

7 0

3 years ago

Calculate the speed of a train that traveled 810 kilometers in 9 hours.

Naya [18.7K]

Answer:

90 kilometers an hour

let me know if I'm wrong

8 0

3 years ago

I'm not really sure how to go about creating the equation, can anyone help me?

AlexFokin [52]

The displacement vector (SI units) is
$\vec{r} =At\hat{i}+A[t^{3}-6t^{2}]\hat{j}$

The speed is a scalar quantity. Its magnitude is
$v= \sqrt{A^{2}t^{2}+A^{2}(t^{3}-6t^{2})^{2}} \\ v=A \sqrt{t^{2}+t^{6}-12t^{5}+36t^{4}} \\ v=At \sqrt{t^{4}-12t^{3}+36t^{2}+1}$

Answer: At√(t⁴ - 12t³ + 36t² + 1)

3 0

3 years ago

15) What is the momentum of a 280 kg motorcycle moving with a velocity of 15 m/s?

enot [183]

Answer:

Explanation:

6 0

2 years ago

A bullet whose mass is 30.2 g leaves a rifle with a muzzle velocity of 1,000 m/s. It strikes a block of wood (mass 5 kg), initia

AveGali [126]

This problem here is an example of inelastic collision where kinetic energy is not conserved but momentum is. We calculate as follows:

m1v1 + m2v2 = (m1 + m2)v3
v3 = m1v1 + m2v2 / m1 + m2
v3 = (30.2)(1000) + (5000)(0) / (30.2 + 5000)
v3 = 6.00 m/s

5 0

3 years ago