Answer:
5295.3 N
Explanation:
According to law of momentum conservation, the change in momentum of the ball shall be from the momentum generated by the batter force
mv + P = mV
P = mV - mv = m(V - v)
Since the velocity of the ball before and after is in opposite direction, one of them is negative
P = 0.14(44.8 - (-19.5)) = 9 kg m/s
Hence the force exerted to generate such momentum within 1.7ms (0.0017s) is 
F = P/t = 9/0.0017 = 5295.3 N
 
        
             
        
        
        
a₀).  You know ... 
         -- the object is dropped from 5 meters 
             above the pavement;
         --  it falls for 0.83 second.
a₁).  Without being told, you assume ... 
         -- there is no air anyplace where the marshmallow travels,
             so it free-falls, with no air resistance;
         -- the event is happening on Earth, 
            where the acceleration of gravity is  9.81 m/s² .
b).  You need to find how much LESS than 5 meters
       the marshmallow falls in 0.83 second.
     
c).  You can use whatever equations you like.
       I'm going to use the equation for the distance an object falls in 
       ' T ' seconds, in a place where the acceleration of gravity is ' G '.
d).  To see how this all goes together for the solution, keep reading: 
The distance that an object falls in ' T ' seconds
when it's dropped from rest is
                                 (1/2 G) x (T²) .
On Earth, ' G ' is roughly  9.81 m/s², so in 0.83 seconds,
such an object would fall
                               (9.81 / 2) x (0.83)² = 3.38 meters .
It dropped from 5 meters above the pavement, but it
only fell 3.38 meters before something stopped it.
So it must have hit something that was
                         (5.00 - 3.38)  =  1.62 meters
above the pavement.  That's where the head of the unsuspecting
person was as he innocently walked by and got clobbered.
        
             
        
        
        
Kinetic Energy = 1/2mv^2
m= 1200kg
v= 24 m/s
KE = 1/2 (1200kg)(24m/s)^2 = 345,600 N
 
        
             
        
        
        
Answer:
A. 2.8 m/s
Explanation:
Suppose that at the height of 0 m, the path of the pendulum is lowest.
If we use law of conservation of energy, the pendulum will have zero kinetic energy or K.E when it is at highest point, because K.E happens during movement of object and at the highest point all the energy will be P.E
                                                     P.E= mgh
Similarly, when the pendulum reaches at the lowest point, the height becomes zero and the P.E also becomes zero. Now all the energy will be K.E
                                                K.E= 1/2 m v^2
In question, we are asked about the speed as the pendulum  it reaches the lowest point of its path. Like we mentioned P.E will be zero at lowest point  because of zero height. And also we will use law of conservation of energy because no energy has been lost from system.
                                                   K.E=     P.E
                                        1/2 m v^2  =   mgh
Taking sq.root at both sides
                                                   v= Under root 2 gh
                                                    v=Under root 2x 9.8 m/s x0.4 m
                                                    v=Under root 7.84
                                                     v=2.8 m/sec
Hope it helps!
 
        
             
        
        
        
Answer:
The himalayan mountain are at a divergent boundary