Using the data for each truck lets calculate,
median for truck 1 - 511.5
median for truck 2 - 650.5
lets consider each statement
A.medians for both trucks are the same - wrong
median for 1 and 2 are 511.5 and 650.5 respectively
B. the two trucks sold most number of tacos on 3rd day
truck 1 sold 437 on day 3 but highest number it sold was 721 on day 1
truck 2 sold 426 on day 3 but highest number was 732 on day 6
therefore this statement too is wrong
C.
truck 1 - range between maximum(721) and minimum(425) = 296
truck 2 - maximum (732) and minimum (426) difference = 306
the range between maximum and minimum in truck 2 is 306 thats greater than range between maximum and minimum in truck 1, that's 296
therefore this statement is correct
D.
total number of tacos for each truck -
truck 1 - 5291
truck 2 - 6107
food truck 1 sold less than truck 2 therefore this statement too is wrong
Ok so you spent 19 dollars the difference between prices is 5 dollars and your answer would be 12 and 7. If you need any help let me know.
Answer:
okay this question i dont know
1st - 2/3 =π√÷
and if tiu substrate that
the answer is 12358063
you can give me the brainliest if u want
final answer-
325
It's a y=mx+b equation, Carries' would be y=1/2 x - 125 (total profit is equal to the cupcake amount, each sold for 50 cents - the startup cost of 125). Juanita's would be y=2.25x-125. Comparing Carries' to Juanita's sales would mean that you would multiply x by 3 (no less than 3 times the ..). I may elaborate further on comparing in the comment section
