Answer:
(a) 283 days
(b) 248 days
Step-by-step explanation:
The complete question is:
The pregnancy length in days for a population of new mothers can be approximated by a normal distribution with a mean of 268 days and a standard deviation of 12 days. (a) What is the minimum pregnancy length that can be in the top 11% of pregnancy lengths? (b) What is the maximum pregnancy length that can be in the bottom 5% of pregnancy lengths?
Solution:
The random variable <em>X</em> can be defined as the pregnancy length in days.
Then, from the provided information
.
(a)
The minimum pregnancy length that can be in the top 11% of pregnancy lengths implies that:
P (X > x) = 0.11
⇒ P (Z > z) = 0.11
⇒ <em>z</em> = 1.23
Compute the value of <em>x</em> as follows:

Thus, the minimum pregnancy length that can be in the top 11% of pregnancy lengths is 283 days.
(b)
The maximum pregnancy length that can be in the bottom 5% of pregnancy lengths implies that:
P (X < x) = 0.05
⇒ P (Z < z) = 0.05
⇒ <em>z</em> = -1.645
Compute the value of <em>x</em> as follows:

Thus, the maximum pregnancy length that can be in the bottom 5% of pregnancy lengths is 248 days.
To find the area of the paper. You must multiply the width and the height, which is 9 and 19.
9 x 19 is 171
And multiply that by 4
171 x 4 = 684
Total area is 684
Answer: D. (-b,0)
applying coordinate geometry practice
the whole quiz >
1. b.
2. a.
3. c.
4. d.
5. c.
6. c.
7. a.
8. d.
9. d.
10. b.
Answer:
x=16/13
y= -9/13
Step-by-step explanation:
A: -4y=-x+4
B: y+3x=3
4B: 4y+12x=12
A+4B: 12x= -x+16
-----> 13x=16
x=16/13
-4y= -16/13+4
4y=16/13-4
y=4/13-1= -9/13