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Answer: The number of times Gavin expect to roll an even number =24
Step-by-step explanation:
Given: Numbers of a fair dice = 1, 2, 3, 4, 5, 6
even numbers = 2, 4, 6
odd numbers = 1, 3, 5
Probability of getting an even number =
If Gavin rolls a fair dice 48 times.
Then, the number of times Gavin expect to roll an even number =
Hence, the number of times Gavin expect to roll an even number =24
Answer: Choice A) There must be a vertical asymptote at x = c
Explanation:
The first limit says that as x approaches c from the left side, the f(x) or y values approach negative infinity. So the graph goes down forever as x approaches this c value from the left side.
The limit means that as x approaches c from the right side, the y values head off to positive infinity.
Either of these facts are enough to conclude that we have a vertical asymptote at x = c. We can think of it like an electric fence in which we can get closer to, but not actually touch it.
Using the normal distribution, it is found that 58.97% of students would be expected to score between 400 and 590.
<h3>Normal Probability Distribution</h3>The z-score of a measure X of a normally distributed variable with mean and standard deviation
is given by:
- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation are given, respectively, by:
The proportion of students between 400 and 590 is the <u>p-value of Z when X = 590 subtracted by the p-value of Z when X = 400</u>, hence:
X = 590:
Z = 0.76
Z = 0.76 has a p-value of 0.7764.
X = 400:
Z = -0.89
Z = -0.89 has a p-value of 0.1867.
0.7764 - 0.1867 = 0.5897 = 58.97%.
58.97% of students would be expected to score between 400 and 590.
More can be learned about the normal distribution at brainly.com/question/27643290
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