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bagirrra123 [75]
3 years ago
8

What expression is equivalent to -9(-5z-2)-7

Mathematics
1 answer:
trapecia [35]3 years ago
4 0
Answer: 45z + 11

Explanation:

-9(-5z - 2) - 7
= 45z + 18 - 7
= 45z + 11
You might be interested in
Which of the following is equivalent to (n-3)(n-5) a. n2-8n+15, b. n2+8n-15, c. n2-15n+8
solong [7]
Foil the binomials

First: n*n=n^2
Outer: n*-5=-5n
Inner: -3*n=-3n
Last: -3*-5=15

Put it together and simplify
n^2-5n-3n+15
n^2-8n+15

Final answer: A
5 0
2 years ago
Gabriel invested $77,000 in an account paying an interest rate of 3%
const2013 [10]

Answer:

Isabella earn 5604.54 more money than  Gabriel

Step-by-step explanation:

As we know

Compound interest (CI) = P (1 + \frac{r}{n})^{nt}

P is the principal amount

t is the time period

n is the number of time periods

r is the rate of interest

a)  CI for  Gabriel

= 77000 (1 + \frac{3}{100*12})^{12*6} = 92165.03 dollars

b) CI for Isabella

= 77000 (1 + \frac{4}{100*4})^{4*6} = 97769.57 dollars

Isabella earn 5604.54 more money than  Gabriel

7 0
2 years ago
PLEASE HELP!!!!<br> I need to solve for a, b, and c
nirvana33 [79]

Answer:

  • 25000 seats in section A
  • 14100 seats in sectin B
  • 10900 seats in section C

Step-by-step explanation:

The problem statement tells you half the total number of seats are in section A, so you already know that there are 25000 A seats. The revenue from those seats is

... 25000×$25 = $625,000

so the revenue from B and C seats must total

... $1,070,500 - 625,000 = $445,500

If all 25000 of the B/C seats were C seats, the revenue would be

... 25000×$15 = $375,000

The actual revenue from those seats is $445,500 -375,000 = $70,500 more than that. We know each B seat generates $5 more revenue, so there must be ...

... $70,500/$5 = 14,100 . . . . B seats

Then the balance of the 25000 B and C seats are C seats:

... 25,000 - 14,100 = 10,900 . . . . C seats

_____

<em>Alternate Solution Method</em>

The new Brainly answer format requires the answer be supplied before the working. In order to find the answer quickly so that I can fill in that section, I used a matrix method for solving the problem. The problem equations can be written ...

  • a + b + c = 50000
  • a - b - c = 0
  • 25a + 20b + 15c = 1070500

so the augmented matrix is ...

\left[\begin{array}{cccc}1&1&1&50000\\1&-1&-1&0\\25&20&15&1070500\end{array}\right]

A graphing calculator can be used to find the solution to this, generally using a function that produces the reduced row-echelon form. The attachment shows the solution using a TI-84 calculator.

___

<em>Comment on the Working</em>

Since the number of A seats is equal to the total of B and C seats, the number of A seats must be half the total number of stadium seats. Having figured that out, the problem is reduced to one of finding the mix of B and C seats that will produce the remaining revenue.

As with many mixture problems, it is convenient to look at differences. Start with the assumption that all of the desired revenue comes from the least contributor. Here, that is C seats. Then figure the difference that using a B seat makes ($20 -15 = $5) and the difference of the actual revenue and the amount that you got by assuming all C seats: 445,500 -375,000 = 70,500. Since replacing a C seat by a B seat adds $5 to the revenue, it is easy to figure the number of such replacements required in order to raise the revenue by $70,500.

If you write the equation for B seats, you find the solution to the equation mirrors this verbal description:

... 20b + 15(25000-b) = 445,500

... 5b = 445,500 - 375000 . . . . simplify, subtract 375000

... b = 70500/5 = 14100

8 0
2 years ago
- 5.8c + 4.2 - 3.1 + 1.4c − 5.8c + 4.2 − 3.1 + 1.4c
Cerrena [4.2K]

Answer:

-8.8c + 2.2 OR SOLVED c = 0.25

Step-by-step explanation:

<u>Step 1:  Combine like terms</u>

- 5.8c + 4.2 - 3.1 + 1.4c − 5.8c + 4.2 − 3.1 + 1.4c

<em>-8.8c + 2.2</em>

<em />

<u>Step 2:  If needed solve for c</u>

-8.8c + 2.2 - 2.2 = 0 - 2.2

-8.8c / -8.8 = -2.2 / -8.8

<em>c = 0.25</em>

<em />

Answer:  -8.8c + 2.2 OR SOLVED c = 0.25

8 0
3 years ago
Read 2 more answers
I NEED HELP PLEASE, THANKS! :)
Alenkasestr [34]

Answer:

Option A

Step-by-step explanation:

This is a great question!

The first thing we want to do here is to graph the system of " inequalities " -

\begin{bmatrix}2x+9y\le \:100\\ 9x+y\le \:54\end{bmatrix}

As x is ≥ 0, respectively y ≥ 0, it makes things a lot simpler, as it kind of restricts us to quadrant 1, but not entirely.

First change each inequality to " slope - intercept " form, as such -

2x + 10y \leq 100,\\10y \leq 100 - 2x,\\y \leq - 1 / 5x + 10\\----------\\9x + y \leq 54,\\y \leq - 9x + 54

The graphed solutions would be in the attachment. I have colored the region with which the two intersect, and the fact that we are limited to quadrant 1. In this colored region there are 3 major points, ( 5, 9 ), ( 0, 10 ), and ( 6, 0 ). We have to determine which of these are are maximum points, as the minimum are the same. Substitute these values ( ( 5, 9 ), ( 0, 10 ), and ( 6, 0 ) ) into the equation f( x, y ) = 10x + 4y,

f ( x, y ) = 10( 5 ) + 4( 9 ),\\f ( x, y ) = 86 -\\f ( x, y ) = 10( 0 ) + 4( 10 ),\\f ( x, y ) = 40 -\\f ( x, y ) = 10( 6 ) + 4( 0 ),\\f ( x, y ) = 60

( 5, 9 ) resulted in the greatest amount, 86. That would make it our maximum point -

<u><em>Solution = Option A</em></u>

3 0
3 years ago
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