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Volgvan
3 years ago
14

There are three quarters, five dimes, and twelve pennies in a bag. When a coin is drawn from the bag, it is replaced. If two coi

ns are drawn at random, determine each probability.
7. P(a quarter and then a penny) 8. P(a nickel and then a dime)
9. P(two pennies) 10. P(a dime and then a quarter)
Please don't just answer for points I actually need help
Mathematics
1 answer:
Allisa [31]3 years ago
3 0

Answer:

9

Step-by-step explanation:

there are 4 more pennies with adding the dimes and quarters together so there is most likely a high probability for 2 pennies to be pulled.

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spin [16.1K]
Okie doke. 1cm on the map equals 500 meters. The distance from the gate to the ferris wheel on the map is 2.5cm. To find the actual distance, multiply the length on the map by the distance per centimeter. 500 * 2.5 is 1,250. The actual distance is 1,250 meters.

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7 0
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A basketball player gets 2 free-throw shots when she is fouled by a player on the opposing team. She misses the first shot 40% o
Semenov [28]
This can easily be answered. Justg use the next formula like this:
<span>0.4*0.05 = 0.02 
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3 0
3 years ago
Read 2 more answers
a line with slope 3 passes through point (0,10). What is the y-coordinate of the point on the line with x-coordinate 2
skad [1K]

The y-coordinate is 16

<h3><u>Solution:</u></h3>

Given that a line with slope 3 passes through point (0, 10)

To find the y-coordinate of the point on the line with x-coordinate 2

Which means the point is (2, y)

Let us find the required y co-ordinate using slope formula

<em><u>The slope of line is given as:</u></em>

For a line containing points (x_1 , y_1) and (x_2 , y_2) is given as:

\text {slope}=m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

\text {Here } x_{1}=0 ; y_{1}=10 ; x_{2}=2 ; y_{2}=y

Given that slope "m" = 3

Substituting the values we get,

\begin{array}{l}{3=\frac{y-10}{2-0}} \\\\ {3=\frac{y-10}{2}} \\\\ {6=y-10} \\\\ {y=10+6=16}\end{array}

Thus the y-coordinate is 16

8 0
3 years ago
Perform the indicated operation. Be sure the answer is reduced.
avanturin [10]
<h3>Given Equation:-</h3>

\boxed{ \rm  \frac{4x^{2}y^{3}z}{9} \times  \frac{45y}{8 {x}^{5} {z}^{5} }}

<h3>Step by step expansion:</h3>

\dashrightarrow \sf\dfrac{4x^{2}y^{3}z}{9} \times  \dfrac{45y}{8 {x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{ \cancel4x^{2}y^{3}z}{9} \times  \dfrac{45y}{ \cancel8 {x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{9} \times  \dfrac{45y}{2{x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{ \cancel9} \times  \dfrac{ \cancel{45}y}{2{x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{x^{2}y^{3}z}{1} \times  \dfrac{5y}{2{x}^{5} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{x^{0}y^{3}z}{1} \times  \dfrac{5y}{2{x}^{5 - 2} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{y^{3}z}{1} \times  \dfrac{5y}{2{x}^{3} {z}^{3} }

\\  \\

\dashrightarrow \sf\dfrac{y^{3}z {}^{0} }{1} \times  \dfrac{5y}{2{x}^{3} {z}^{3 - 1} }

\\  \\

\dashrightarrow \sf\dfrac{y^{3}}{1} \times  \dfrac{5y}{2{x}^{3} {z}^{2} }

\\  \\

\dashrightarrow \sf  \dfrac{5y \times  {y}^{3} }{2{x}^{3} {z}^{2} }

\\  \\

\dashrightarrow \sf  \dfrac{5y {}^{0}  \times  {y}^{3 + 1} }{2{x}^{3} {z}^{2} }

\\  \\

\dashrightarrow \sf  \dfrac{5 \times  {y}^{4} }{2{x}^{3} {z}^{2} }

\\  \\

\dashrightarrow \bf  \dfrac{5 {y}^{4} }{2{x}^{3} {z}^{2} }

\\  \\

\therefore \underline{ \textbf{ \textsf{option \red c \: is \: correct}}}

8 0
2 years ago
Help me please! Thx
ruslelena [56]

Answer:

9/5

Step-by-step explanation:

6 0
3 years ago
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