Answer:
The property used is the commutative property.
Step-by-step explanation:
In the commutative property, the sum is the same if you reorder the numbers.
I hope this helped! :-)
Answer with explanation:
For any object having the velocity vector as
![\overrightarrow{v}=v_x\widehat{i}+v_y\widehat{j}+v_z\widehat{k}](https://tex.z-dn.net/?f=%5Coverrightarrow%7Bv%7D%3Dv_x%5Cwidehat%7Bi%7D%2Bv_y%5Cwidehat%7Bj%7D%2Bv_z%5Cwidehat%7Bk%7D)
the magnitude of velocity is given by
![|v|=\sqrt{v_x^2+v_y^2+v_z^2}](https://tex.z-dn.net/?f=%7Cv%7C%3D%5Csqrt%7Bv_x%5E2%2Bv_y%5E2%2Bv_z%5E2%7D)
For car 1 the velocity vector is
![\overrightarrow{v}_1=20\widehat{i}+25\widehat{j}](https://tex.z-dn.net/?f=%5Coverrightarrow%7Bv%7D_1%3D20%5Cwidehat%7Bi%7D%2B25%5Cwidehat%7Bj%7D)
Therefore
![|v_1|=\sqrt{20^2+25^2}\\\\\therefore v_1=32.0156units](https://tex.z-dn.net/?f=%7Cv_1%7C%3D%5Csqrt%7B20%5E2%2B25%5E2%7D%5C%5C%5C%5C%5Ctherefore%20v_1%3D32.0156units)
Similarly for car 2 we have
![\overrightarrow{v}_2=30\widehat{i}](https://tex.z-dn.net/?f=%5Coverrightarrow%7Bv%7D_2%3D30%5Cwidehat%7Bi%7D)
Therefore
![|v_2|=\sqrt{30^2}\\\\\therefore v_2=30.0units](https://tex.z-dn.net/?f=%7Cv_2%7C%3D%5Csqrt%7B30%5E2%7D%5C%5C%5C%5C%5Ctherefore%20v_2%3D30.0units)
Comparing both the values we find that car 1 has the greater speed.
Answer:
180
Step-by-step explanation:
guessed the answer
that was the easiest
Answer:
hotogs=$1.50 hamburgers=$1
Step-by-step explanation:
h=hotdog b=hamburger
7h+4b=13
4h+7b=14.5
(7h+4b=13)-4b
4h+7b=14.5
h=-0.57b+1.86
4h+7b=14.5
Answer:
3
Step-by-step explanation:
I searched it up on the web