All categories

2 years ago

Please help me and type out the answer

Mathematics

2 answers:

Orlov [11]2 years ago

3 0

Answer:

The owner makes $2 in sales per customer

Note: The "Amount of sales" label of the question is phrased poorly. s could be better labeled "profit from sales" or at least "Amount made from sales", etc.

Step-by-step explanation:

If you logically think about how the answer (now that you know it) relates to the question, it should make simple sense.

i.e. if you consider the first column where $24 is made from 12 customers, and divide the $24 made by the 12 customers, you'll see that each customer spends $2.

skelet666 [1.2K]2 years ago

3 0

Answer:

the owner makes 2 dollars in sales every week

Step-by-step explanation:

on the chart/graph it shows 6 new customers every week and if you want to see how much more money the owner makes off of each customer then...

subtract the first weeks number of customers from the second weeks to get the answer of 6 new customers per week as you can see on the chart/graph (this really isnt to important though)

then divide the total number of customers for 1 week by the profits made for that week to get an answer of 2 dollars for customers.

(i hope you understand because i just confused myself with my own explanation)

You might be interested in

Ben and Josh went to the roof of their 40-foot tall high school to throw their math books offthe edge.The initial velocity of Be

Taya2010 [7]

Answer

Josh's textbook reached the ground first

Josh's textbook reached the ground first by a difference of $t=0.6482$

Step-by-step explanation:

Before we proceed let us re write correctly the height equation which in correct form reads:

$h(t)=-16t^2 +v_{o}t+s$ Eqn(1).

Where:

$h(t)$ : is the height range as a function of time

$v_{o}$ : is the initial velocity

$s$ : is the initial heightin feet and is given as 40 feet, thus Eqn(1). becomes:

$h(t)=-16t^2 + v_{o}t + 40$ Eqn(2).

Now let us use the given information and set up our equations for Ben and Josh.

Ben:

We know that $v_{o}=60ft/s$

Thus Eqn. (2) becomes:

$h(t)=-16t^2+60t+40$ Eqn.(3)

Josh:

We know that $v_{o}=48ft/s$

Thus Eqn. (2) becomes:

$h(t)=-16t^2+48t+40$ Eqn. (4).

Now since we want to find whose textbook reaches the ground first and by how many seconds we need to solve each equation (i.e. Eqns. (3) and (4)) at $h(t)=0$ . Now since both are quadratic equations we will solve one showing the full method which can be repeated for the other one.

Thus we have for Ben, Eqn. (3) gives:

$h(t)=0-16t^2+60t+40=0$

Using the quadratic expression to find the roots of the quadratic we have:

$t_{1,2}=\frac{-b+/-\sqrt{b^2-4ac} }{2a} \\t_{1,2}=\frac{-60+/-\sqrt{60^2-4(-16)(40)} }{2(-16)} \\t_{1,2}=\frac{-60+/-\sqrt{6160} }{-32} \\t_{1,2}=\frac{15+/-\sqrt{385} }{8}\\\\t_{1}=4.3276 sec\\t_{2}=-0.5776 sec$