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3 years ago

Evaluate 1/3y+8/15 when y=1/5

Mathematics

1 answer:

maks197457 [2]3 years ago

4 0

Answer: 0.6

Why: 1/3 * 1/5= 0.066
0.066+8/15= 0.6

Hope this Helps :D

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What is the relationship between the continental drift hypothesis and the theory of

Pepsi [2]

Answer:

Plate tectonics explains why Earth's continents are moving; the theory of continental drift did not provide an explanation. Therefore, the theory of plate tectonics is more complete. It has gained widespread acceptance among scientists.

Step-by-step explanation:

Do some research on it.

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2 years ago

If 7 p − 4 = 8 , 7p−4=8, what is the value of p ?

Nookie1986 [14]

Hello!

Let's solve our equation below.

7p-4=8

First we add 4 to both sides.

7p=12

We divide both sides by 7.

p≈1.71

I hope this helps!

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3 years ago

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Consider the following functions. f={(−4,−1),(1,1),(−3,−2),(−5,2)} and g={(1,1),(2,−3),(3,−1)}: Find (f−g)(1).

fenix001 [56]

Answer:

Step-by-step explanation:

Subtraction of functions has the property:

(f−g)(1) = f(1) - g(1)

f={(−4,−1),(1,1),(−3,−2),(−5,2)} has (1,1) means that f maps 1 to 1, therefore f(1) = 1

g={(1,1),(2,−3),(3,−1)} has (1,1), means that g maps 1 to 1, therefore g(1)=1

As a Result, since (f−g)(1) = f(1) - g(1), we have (f−g)(1) = 1-1=0

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3 years ago

Monique's son just turned 2 years old and is 34 inches tall. Monique heard that the average boy will grow approximately 2 5/8 in

tatuchka [14]

Answer:

The equation representing how old Monique son is $\mathbf{a = 2 + \dfrac{8}{21}(q-34)}$

Step-by-step explanation:

From the given information:

A linear function can be used to represent the constant growth rate of Monique Son.

i.e.

$q(t) = \hat q \times t + q_o$

where;

$q_o$ = initial height of Monique's son

$\hat q$ = growth rate (in)

t = time

So, the average boy grows approximately 2 5/8 inches in a year.

i.e.

$\hat q = 2 \dfrac{5}{8} \ in/yr$

$\hat q = \dfrac{21}{8} \ in/yr$

Then; from the equation $q(t) = \hat q \times t + q_o$

$34 = \dfrac{21}{8} \times 0 + q_o$

$q_o = 34\ inches$

The height of the son as a function of the age can now be expressed as:

$q(t) = \dfrac{21}{8} \times t + 34$

Then:

Making t the subject;

$q - 34 = \dfrac{21}{8} \times t$

$t = \dfrac{8}{21}(q-34)$

and the age of the son i.e. ( a (in years)) is:

a = 2 + t

So;

$\mathbf{a = 2 + \dfrac{8}{21}(q-34)}$

SO;

if q (growth rate) = 50 inches tall

Then;

$\mathbf{a = 2 + \dfrac{8}{21}(50-34)}$

$\mathbf{a = 2 + \dfrac{8}{21}(16)}$

a = 2 + 6.095

a = 8.095 years

a ≅ 8 years

i.e.

Monique son will be 8 years at the time Monique is 50 inches tall.

8 0

2 years ago

Ezra is training for a track race. He starts by sprinting 100 yards. He gradually increases his distance, adding 5 yards a day f

Sergeu [11.5K]

On the 21st day, he sprints 205 yards.

Is that what you meant for the problem

or do u want to know how many yards he sprinted total for the 21 days
If it is,
he sprinted a total of 3390 yards

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3 years ago

Read 2 more answers