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balu736 [363]
3 years ago
11

Plz help me out with the 'd' one​

Mathematics
1 answer:
Effectus [21]3 years ago
5 0

Answer:

381/90

Step-by-step explanation:

x = 4.2333.... ----------(I)

Number of digit after decimal is 2 ( 4 , 3). So multiply both sides by of equation 100

100x = 423.333..... (II)

One digit (3) is repeating.So, multiply by both sides of equation (I) by 10

10x = 42.333....... -----(III)

Subtract Equation (III) from (II)

(II)     100x = 423.333......

(III)        <u>10x =  42.333......</u>  {Subtract}

         90x   = 381

                x = 381/90

<u />

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Read 2 more answers
A research group needs to determine a 90% confidence interval for the mean repair cost for all car insurance small claims. From
lutik1710 [3]

Answer:

a) z = 1.645

b) The should sample at least 293 small claims.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.05 = 0.95, so z = 1.645, which means that the answer of question a is z = 1.645.

Now, find  the margin of error M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

(b) If the group wants their estimate to have a maximum error of $12, how many small claims should they sample?

They should sample at least n small claims, in which n is found when

M = 12, \sigma = 124.88. So

M = z*\frac{\sigma}{\sqrt{n}}

12 = 1.645*\frac{124.88}{\sqrt{n}}

12\sqrt{n} = 205.43

\sqrt{n} = \frac{205.43}{12}

\sqrt{n} = 17.12

\sqrt{n}^{2} = (17.12)^{2}

n = 293

The should sample at least 293 small claims.

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Step-by-step explanation:

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