For a cartesian equation

Given r = <span>10 tan(θ) sec(θ)

Therefore,</span>the curve is a parabola opening upward with vertex (0, 0).
Answer:
48+12b≥185
Step-by-step explanation:
Inequality: 48+12b≥185
Why? she has already backed 48 cookies so you just need to find how many more she needs to bake. (she doesn't need 185 cookies anymore since she's already baked 48)
You don' t need to solve the question,
But here is how you do...
12b≥137
b≥11.42 (roughly)
Answer:
$681.60
Step-by-step explanation:
<u><em>Given:</em></u>
<em>During a sale, a store offered a 20% discount on a TV that originally sold for $710. After the sale, the discounted price of the TV was marked up by 20%</em>
<u><em>To Find:</em></u>
<em>What was the price of the TV after the markup? Round to the nearest cent.</em>
<u><em>Solution:</em></u>
$710 × (1 + 20%) × (1 - 20%)
$710 × 1.2 × (1-0.2)
$710 × 1.2 × 0.8
($710 × 1.2) × 0.8
852 × 0.8
= $681.60
<u><em>Kavinsky</em></u>
Answer:
The solution is
.
Step-by-step explanation:
Given:
The inequality given is:

In order to simplify for 'x', we first isolate 'x' on one side.
Adding -4 on both sides, we get:

Now,
is an absolute value function which is defined as:

Therefore, the given inequality can be rewritten as:
and 
Therefore, the solution is
.
0^9 +7x+189yx−3y
o
9
+7x−3y
9
+7x+3y
9
−7x−3y
9
−7x+3y
9
+7x+189yx−3y
2 Collect like terms.
{o}^{9}+(7x+7x-7x-7x+7x)+(-3{y}^{9}+3{y}^{9}-3{y}^{9}+3{y}^{9})+189yx-3y
o
9
+(7x+7x−7x−7x+7x)+(−3y
9
+3y
9
−3y
9
+3y
9
)+189yx−3y
3 Simplify.
{o}^{9}+7x+189yx-3y
o
9
+7x+189yx−3y