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Masteriza [31]
4 years ago
5

GETS BRAINILIST!!!!The table shows the relationship between the number of drops of food color added to different number of cups

of cake frosting: Cups of Frosting Drops of Food Color 2 4 3 6 4 8 Which point below shows an equivalent ratio in this situation? A graph is shown. The title of the graph is Cake Decorating. The horizontal axis label is Frosting in cups. The horizontal axis values are 0, 10, 20, 30, 40, 50, 60. The vertical axis label is Food Color in drops. The vertical axis values are 0, 20, 40, 60, 80, 100, 120. Point T is plotted on the ordered pair 50, 100, and Point G is plotted on the ordered pair 40, 20. Point T, because if drops of food coloring are 50, then cups of frosting will be 100 Point G, because if cups of frosting are 40, then drops of food coloring will be 20 Point T, because if cups of frosting are 50, then drops of food coloring will be 100 Point G, because if drops of food coloring are 40, then cups of frosting will be 20
Mathematics
1 answer:
Kryger [21]4 years ago
8 0

Answer:

I would say the first one

Step-by-step explanation:

A graph is shown. The title of the graph is Cake Decorating. The horizontal axis label is Frosting in cups. The horizontal axis values are 0, 10, 20, 30, 40, 50, 60. The vertical axis label is Food Color in drops. The vertical axis values are 0, 20, 40, 60, 80, 100, 120.

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Construct the indicated confidence interval for the difference between the two population means. Assume that the two samples are
jasenka [17]

Answer:

The indicated confidence interval for the difference between the two population means is  (-1.5159, 7.5159)

Step-by-step explanation:

Let the drying times of type A be the first population and the drying times of type B be the second population. Then

We have small sample sizes n_{1} = 11 and n_{2} = 9, besides \bar{x}_{1} = 71.5, s_{1} = 3.4 , \bar{x}_{2} = 68.5 and s_{2} = 3.6. Therefore, the pooled

estimate is given by  

s_{p}^{2} = \frac{(n_{1}-1)s_{1}^{2}+(n_{2}-1)s_{2}^{2}}{n_{1}+n_{2}-2} = \frac{(11-1)(3.4)^{2}+(9-1)(3.6)^{2}}{11+9-2} = 12.1822

The 99% confidence interval for the true mean difference between the mean drying time of type A and the mean drying time of type B is given by

(\bar{x}_{1}-\bar{x}_{2})\pm t_{0.01/2}s_{p}\sqrt{\frac{1}{11}+\frac{1}{9}}, i.e.,

(71.5-68.5)\pm t_{0.005}(3.4903)\sqrt{\frac{1}{11}+\frac{1}{9}}

where t_{0.005} is the 0.5th quantile of the t distribution with (11+9-2) = 18 degrees of freedom. So

3\pm(-2.8784)(3.4903)(0.4495), i.e.,

the indicated confidence interval for the difference between the two population means is  (-1.5159, 7.5159)

5 0
3 years ago
Find the value of 1/2×3/5 +1/2×2/5 by using suitable property.<br>please answer this friends​
kolbaska11 [484]

Answer:

\frac{1}{2}

Step-by-step explanation:

Given

\frac{1}{2} × \frac{3}{5} + \frac{1}{2} × \frac{2}{5} ( perform multiplication before addition )

= \frac{3}{10} + \frac{2}{10}

= \frac{5}{10} ( divide numerator/ denominator by 5 to simplify )

= \frac{1}{2}

5 0
3 years ago
Read 2 more answers
Partway through the season, a basketball coach promises his team that he will take them to a water park if they reach 1,000 poin
velikii [3]
From the given above, the point that still needs to be incurred by the group is calculated by subtracting 424 points from 1000. This as shown below,

       n = 1000 - 424  = 576

If we are to determine the number of points each game, we divide 576 by 9. That is,
         x = 576 / 9 = 64

<em>ANSWER: 64 points/ game</em>
7 0
3 years ago
How did they get 1.5
Nonamiya [84]
ANSWER:
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explanation:


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3 years ago
A local business has an area reserved behind the store for a parking lot that is 78 meters long by 19 meters wide. The stalls of
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The total area available for cars to park will be 858m².

<h3>How to calculate the area?</h3>

The area of the parking lot will be:

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The available area will be:

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N × 12.5 = 858

N = 858/12.5

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The non compact parking spaces that will fit in the lot will be:

N × 16.5 = 858

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N = 52

Learn more about area on:

brainly.com/question/7438648

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