Answer:
U=α/(x+x_0)^2
v=1.88m/s
Explanation:
We have that
(a)
The potential is calculated by using
(b)
m=0.5kg
The acceleration can be obtained if we calculate the force for x=4, and after we compute the acceleration
and finally, we can use the equation for the final speed
I hope this is useful for you
regards
Answer:
Explanation:
Assuming this problem: "Carbon dioxide enters an adiabatic nozzle at 1200 K with a velocity of 50 m/s and leaves at 400 K. Assuming constant specific heats at room temperature, determine the Mach number (a) at the inlet and (b) at the exit of the nozzle. Assess the accuracy of the constant specific heat assumption."
Part a
For this case we can assume at the inlet we have the following properties:
We can calculate the Mach number with the following formula:
Where k represent the specific ratio given k =1.288 and R would be the universal gas constant for the carbon diaxide given by:
And if we replace we got:
Part b
For this case we can use the same formula:
And we can obtain the value of v2 from the total energy of adiabatic flow process, given by this equation:
The value of and the value fo T2 = 400 K so we can solve for and we got:
And now we can replace on this equation:
And we got:
Answer is B. Conduction
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Conduction is a heat it transferred to the heat by touching your hand.
Hope it helped you.
-Charlie
Answer:
F = 35651 [N]
Explanation:
To solve this problem we must use Newton's second law, which tells us that the sum of forces is equal to the product of mass by acceleration.
But first, we must use the following equation of kinematics to find acceleration.
where:
Vf = final velocity = 185 [m/s]
Vi = initial velocity = 0 (the cannon ball is at rest in the first moment)
a = acceleration [m/s²]
x = distance = 3.6 [m]
Now replacing these values into the equation:
(185)² = 0² + (2*a*3.6)
34225 = 7.2*a
a = 34225/7.2
a = 4753.5 [m/s²]
Now using Newton's second law we have:
F = m*a
where:
F = force [N]
m = mass = 7.5 [kg]
F = 7.5*4753.5
F = 35651 [N]
Answer:
12.68 m/s.
Explanation:
Equations of motion:
i. S = vi*t + 1/2 * a*(t^2)
ii. vf = vi + a*t
iii. vf^2 = vi^2 + 2a*S
Where, vf = final velocity
vi = initial velocity
S = distance travelled
a = acceleration due to gravity
t = time taken
Given:
vi = 0 m/s
S = 8.2 m
vf = ?
a = 9.81 m/s^2
Using iii. Equation of motion,
vf^2 = vi^2 + 2a*S
= 2 * 9.81 * 8.2
= 160.884
vf = sqrt (160.884)
= 12.68 m/s.