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andrey2020 [161]
3 years ago
13

A cardio kickboxing class challenges 3 things. List them.

Physics
1 answer:
bagirrra123 [75]3 years ago
6 0

Answer:

In a cardio kickboxing class, you will learn proper form for the famous jab, hooks,crosses, uppercuts, back kicks, front kicks.

Explanation:

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(3) A Ninja motorcycle is moving down I95 at 160 miles per hour (72 m/s) and a cop uses a radar gun to measure the speed. Using
Virty [35]

Answer:

it does use it at doppler

Explanation:

My dad told me the hes a cop so yw

5 0
3 years ago
Which of the following statements best describes the definition of<br> distance?
ch4aika [34]

Explanation:

  • The distance covered by a body is equal to the sum of total path covered. It is equal to the total path traveled by an object during its entire journey.
  • This quantity is always positive. It can't be 0 or a negative number.
  • It is defined as a scalar quantity.
  • Mathematically, it can be calculated as follows :

distance = speed × time

5 0
3 years ago
A device is rated at 1.3kW when connected to a 120 V source. The equivalent resistance of this device in ohm is:
alexdok [17]

Answer:

D.

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7 0
3 years ago
If a 15 N box is lifted a distance of 3 m, how much work is done?
Naily [24]

Answer:

W=45J

Explanation:

W=Fd

W=15(3)=45

W=45J

7 0
3 years ago
Read 2 more answers
a 3.5 kg mass has an initial velocity of 4.0 m/s. How much force is required to increase the velocity of the mass to 8.0 m/s in
Nadya [2.5K]

Answer:

<em>4.67 N of force are required</em>

Explanation:

The second Newton's law states the net force exerted on a body of mass m that has an acceleration a, is given by:

F=m.a

On the other hand, the kinematics equations relate the acceleration with the change of speed over time, expressed as:

\displaystyle a=\frac{v_f-v_o}{t}

We are given the initial speed of vo=4 m/s on a mass of m=3.5 Kg, the final speed of vf=8 m/s which took t=3 seconds.

The acceleration is:

\displaystyle a=\frac{8-4}{3}=1.33

a=1.33\ m/s^2

Thus, the force is:

F=3.5\ Kg\cdot 1.33\ m/s^2

F=4.67\ N

4.67 N of force are required

6 0
3 years ago
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