Two carts (m1 = m2 = 0.400 kg) are placed on an aluminum track. The first cart is pushed with the initial velocity of 1.5 m/s to
wards the second cart, which remains at rest until the collision. Determine the velocities of both carts after the collision. (5)
V1 = __________ m/s, V2 = __________ m/s,
V1 = __________ m/s, V2 = __________ m/s,
1 answer:
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Answer:
Gauge Pressure required = 606.258 kPa
Explanation:
Water will not enter the chamber if the pressure of air in it equals that of the water which tries to enter it.
Thus at a depth of 60m we have pressure of water equals
Now the gauge pressure is given by
Applying values we get
Answer:
24 N
Explanation:
= mass of the cube =
Consider the three cubes together as one.
= mass of the three cubes together =
= acceleration of the combination = 2 ms⁻²
= Force applied on the combination
Using Newton's second law
= Force by the left cube on the middle cube
Consider the forces acting on left cube, from the force diagram, we have
