Two carts (m1 = m2 = 0.400 kg) are placed on an aluminum track. The first cart is pushed with the initial velocity of 1.5 m/s to
wards the second cart, which remains at rest until the collision. Determine the velocities of both carts after the collision. (5)
V1 = __________ m/s, V2 = __________ m/s,
V1 = __________ m/s, V2 = __________ m/s,
1 answer:
You might be interested in
The water pressure on the first floor must be 455 PSI in order to push the water to the 13th floor at the given pressure.
The given parameters;
- <em>Pressure on the 13 th floor, P₁ = 35 PSI</em>
- <em>Distance between each floor, d = 10 ft</em>
The vertical pressure of the water is calculated as follows;
The vertical height of the first floor from the 13th floor = 130 ft
The vertical height of the 13 ft floor = 10 ft
Thus, the water pressure on the first floor must be 455 PSI in order to push the water to the 13th floor at the given pressure.
Learn more about vertical height and pressure here: brainly.com/question/15691554
Answer:
Explanation:
1+7 = 6+2 =8 -protons
1+15 = 12+4 = 16 - protons +neutrons
To solve this problem we need to apply the corresponding sound intensity measured from the logarithmic scale. Since in the range of intensities that the human ear can detect without pain there are large differences in the number of figures used on a linear scale, it is usual to use a logarithmic scale. The unit most used in the logarithmic scale is the decibel yes described as
Where,
I = Acoustic intensity in linear scale
= Hearing threshold
The value in decibels is 17dB, then
Using properties of logarithms we have,
Therefore the factor that the intensity of the sound was