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mario62 [17]
4 years ago
13

If 8 people share a half pound of pasta how much would each get​

Mathematics
2 answers:
Nataly [62]4 years ago
5 0

Answer:

1/16

Step-by-step explanation:

to see how much each person get you need to divide 1/2 by 8

1/2 divided by 8

Now u have to flip the sign to multiplication and the 8 turns into 1/8

1/2 times 1/8=

1/16

12345 [234]4 years ago
3 0

Answer: 1/16

<u>Do Keep Change Flip (KCF)</u>

Keep: 1/2

Change: ÷ into ×

Flip: 8/1 into 1/8

Your New Problem Should Be: 1/2×1/8

<u>Multiply</u>

1/2 × 1/8 = 1/16

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What is the halfway point between 12 and 13<br>Is that point closer to 12 or 13?​
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Answer:

12.5

Step-by-step explanation:

The point is closer to 13 because you round up

7 0
3 years ago
What is five sixths divided by nine thirds?
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0.270.27777777777

Step-by-step explanation:

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3 years ago
Use the form of the definition of the integral given in the theorem to evaluate the integral. ∫ 0 − 2 ( 7 x 2 + 7 x ) d x
Murrr4er [49]

Answer:

\int _{-2}^07x^2+7xdx=\frac{14}{3}

Step-by-step explanation:

The definite integral of a continuous function <em>f</em> over the interval [a,b] denoted by \int\limits^b_a {f(x)} \, dx, is the limit of a Riemann sum as the number of subdivisions approaches infinity. That is,

\int\limits^b_a {f(x)} \, dx=\lim_{n \to \infty} \sum_{i=1}^{n}\Delta x \cdot f(x_i)

where \Delta x = \frac{b-a}{n} and x_i=a+\Delta x\cdot i

To evaluate the integral

\int\limits^{0}_{-2} {7x^{2}+7x } \, dx

you must:

Find \Delta x

\Delta x = \frac{b-a}{n}=\frac{0+2}{n}=\frac{2}{n}

Find x_i

x_i=a+\Delta x\cdot i\\x_i=-2+\frac{2i}{n}

Therefore,

\lim_{n \to \infty}\frac{2}{n} \sum_{i=1}^{n} f(-2+\frac{2i}{n})

\int\limits^{0}_{-2} {7x^{2}+7x } \, dx=\lim_{n \to \infty}\frac{2}{n} \sum_{i=1}^{n} 7(-2+\frac{2i}{n})^{2} +7(-2+\frac{2i}{n})

\lim_{n \to \infty}\frac{2}{n} \sum_{i=1}^{n} 7(-2+\frac{2i}{n})^{2} +7(-2+\frac{2i}{n})\\\\\lim_{n \to \infty}\frac{2}{n} \sum_{i=1}^{n} 7[(-2+\frac{2i}{n})^{2} +(-2+\frac{2i}{n})]\\\\\lim_{n \to \infty}\frac{14}{n} \sum_{i=1}^{n} (-2+\frac{2i}{n})^{2} +(-2+\frac{2i}{n})\lim_{n \to \infty}\frac{14}{n} \sum_{i=1}^{n} (-2+\frac{2i}{n})^{2} +(-2+\frac{2i}{n})\\\\\lim_{n \to \infty}\frac{14}{n} \sum_{i=1}^{n} 4-\frac{8i}{n}+\frac{4i^2}{n^2} -2+\frac{2i}{n}\\\\\lim_{n \to \infty}\frac{14}{n} \sum_{i=1}^{n} \frac{4i^2}{n^2}-\frac{6i}{n}+2

\lim_{n \to \infty}\frac{14}{n} \sum_{i=1}^{n} \frac{4i^2}{n^2}-\frac{6i}{n}+2\\\\\lim_{n \to \infty}\frac{14}{n}[ \sum_{i=1}^{n} \frac{4i^2}{n^2}-\sum_{i=1}^{n}\frac{6i}{n}+\sum_{i=1}^{n}2]\\\\\lim_{n \to \infty}\frac{14}{n}[ \frac{4}{n^2}\sum_{i=1}^{n}i^2 -\frac{6}{n}\sum_{i=1}^{n}i+\sum_{i=1}^{n}2]

We can use the facts that

\sum_{i=1}^{n}i^2=\frac{n(n+1)(2n+1)}{6}

\sum_{i=1}^{n}i=\frac{n(n+1)}{2}

\lim_{n \to \infty}\frac{14}{n}[ \frac{4}{n^2}\cdot \frac{n(n+1)(2n+1)}{6}-\frac{6}{n}\cdot  \frac{n(n+1)}{2}+2n]\\\\\lim_{n \to \infty}\frac{14}{n}[-n+\frac{2\left(n+1\right)\left(2n+1\right)}{3n}-3]\\\\\lim_{n \to \infty}\frac{14\left(n^2-3n+2\right)}{3n^2}

\frac{14}{3}\cdot \lim _{n\to \infty \:}\left(\frac{n^2-3n+2}{n^2}\right)\\\\\mathrm{Divide\:by\:highest\:denominator\:power:}\:1-\frac{3}{n}+\frac{2}{n^2}\\\\\frac{14}{3}\cdot \lim _{n\to \infty \:}\left(1-\frac{3}{n}+\frac{2}{n^2}\right)\\\\\frac{14}{3}\left(\lim _{n\to \infty \:}\left(1\right)-\lim _{n\to \infty \:}\left(\frac{3}{n}\right)+\lim _{n\to \infty \:}\left(\frac{2}{n^2}\right)\right)\\\\\frac{14}{3}\left(1-0+0\right)\\\\\frac{14}{3}

Thus,

\int _{-2}^07x^2+7xdx=\frac{14}{3}

5 0
4 years ago
Name something that often has an inscription and describe what it would say
strojnjashka [21]
Definition a brief informal dedication as of a book or a work of art
6 0
3 years ago
Please help!! Would be appreciated:)
Art [367]

Answer:

A. 21

B. 19

Step-by-step explanation:

Happy to help!

:D

6 0
2 years ago
Read 2 more answers
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