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melamori03 [73]

2 years ago

5

What is the sign of the product (-7)(-2)(-5)(1)? (5 points) ]

1 answer:

DIA [1.3K]2 years ago

4 0

As a rule the product of an ODD number of NEGATIVE SIGNS is always NEGATIVE

An the product of an EVEN number of NEGATIVE SIGNS is always POSITIVE
Then the following statement is the right one:
Negative, because the product (-7)(-2) is positive, and the product (-5)(1) is negative and the product of a positive and a negative number is negative

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Answer:

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Step $1$

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<u>Find the length of the segment AB</u>

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Step $2$

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we know that

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Step $3$

In the right triangle ABC

<u>Find the length of the segment AC</u>

we know that

$cos(BAC)=cos (BAD)=\frac{5}{13}$

$cos(BAC)=\frac{adjacent\ side }{hypotenuse}=\frac{AB}{AC}$

$\frac{5}{13}=\frac{AB}{AC}$

$\frac{5}{13}=\frac{13}{AC}$

solve for AC

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Step $4$

<u>Find the length of the segment DC</u>

we know that

$DC=AC-AD$

we have

$AC=33.8\ units$

$AD=5\ units$

substitute the values

$DC=33.8\ units-5\ units$

$DC=28.8\ units$

Step $5$

<u>Find the length of the segment BC</u>

In the right triangle BDC

Applying the Pythagorean Theorem

$BC^{2} =BD^{2}+DC^{2}$

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$BD=12\ units\\DC=28.8\ units$

substitute the values

$BC^{2}=12^{2}+28.8^{2}$

$BC^{2}=973.44$

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therefore

<u>the answer is</u>

$BC=31.2\ units$

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