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jekas [21]
3 years ago
5

Two of what geometric figures are joined at a vertex to form an angle

Mathematics
2 answers:
kvasek [131]3 years ago
7 0

Answer:

C) rays

Step-by-step explanation:

Two rays are joined at a vertex to form an angle.

Hope this helps :)

bija089 [108]3 years ago
5 0

Answer:

point (A)

Step-by-step explanation:

it is ez

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7,896,123.5 place value of 7
slamgirl [31]

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3 0
3 years ago
What is a<br> decomposition reaction?
yaroslaw [1]

Answer:

11-6√3 = a -b√3

where a=11 and b =6

Step-by-step explanation:

<u><em>Step(i):-</em></u>

Given

      \frac{5+2\sqrt{3} }{7+4\sqrt{3} }

Rationalize

=    \frac{5+2\sqrt{3} }{7+4\sqrt{3} } X \frac{7-4\sqrt{3} }{7-4\sqrt{3} }

=    \frac{(5+2\sqrt{3})(7-4\sqrt{3} ) }{7^{2} -(4\sqrt{3})^{2}  }

=  \frac{(5+2\sqrt{3})(7-4\sqrt{3} ) }{49-16(3)  }

= \frac{(5+2\sqrt{3})(7-4\sqrt{3} ) }{1  }

<u><em>Step(ii):-</em></u>

<em>Multiply</em>

<em>     </em>{(5+2\sqrt{3})(7-4\sqrt{3} ) }

=  5 × 7 - 5×4√3 + 2√3 ×7 - 2√3 × 4√3

= 35 -20√3+ 14√3-8×3

= 35 - 6√3 -24

= 11-6√3

6 0
3 years ago
Describe the nature of the roots for this equation, x^2-2x+1=0
zimovet [89]
Use the discrimant to determine the nature of the roots
Here's the formula of the discriminant from the equation ax²+bx+c = 0
D = b² - 4ac

If the discriminant is greater than 0, the quadratic equation has 2 real different roots
If the discriminant is equal to 0, the quadratic equation has only one real root.
If the discriminant is less than 0, the quadratic equation doesn't have real root.

Find the discriminant of the equation x² - 2x + 1 = 0
D = b² - 4ac
D = (-2)² - 4(1)(1)
D = 4 - 4
D = 0
The equation has only one real root.
5 0
4 years ago
What does x equal in -3+5x=-26
Tcecarenko [31]
X = -4.6
-3+(5x4.6)=-26
4 0
4 years ago
PLS HELP
Charra [1.4K]

Answer:  -418, 728, 446, -429, 1159, -696

Step-by-step explanation:

1. n = -199 - 219 = \boxed{-418}.

2. m = 438 - (-290) = 438 + 290 = \boxed{728}.

3. 128 - (-318) = 128 + 318 = \boxed{446}.

4. The sum of 429 and 429 is 429+429 = 858. We need to subtract this from 429, so 429 - 858 = \boxed{-429}.

5. The sum of 510 and 319 is 510+319 = 829. Subtracting -330, we get 829 - (-330) = 829 + 330 = \boxed{1159}.

6. Call the unknown number "\star". Then \star + 298 = -398, so \star = -398 - 298 = \boxed{-696}. (Think about it.)

4 0
3 years ago
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