Now cos⁻¹(0.7) is about 45.6°, that's on the first quadrant.
keep in mind that the inverse cosine function has a range of [0, 180°], so any angles it will spit out, will be on either the I quadrant where cosine is positive or the II quadrant, where cosine is negative.
however, 45.6° has a twin, she's at the IV quadrant, where cosine is also positive, and that'd be 360° - 45.6°, or 314.4°.
now, those are the first two, but we have been only working on the [0, 360°] range.... but we can simply go around the circle many times over up to 720° or 72000000000° if we so wish, so let's go just one more time around the circle to find the other fellows.
360° + 45.6° is a full circle and 45.6° more, that will give us the other angle, also in the first quadrant, but after a full cycle, at 405.6°.
then to find her twin on the IV quadrant, we simply keep on going, and that'd be at 360° + 360° - 45.6°, 674.4°.
and you can keep on going around the circle, but only four are needed this time only.
Answer:
No
Step-by-step explanation:
It is not divisible by 6, for if you divide by 6, you will get a non natural number,
It is obviously divisible by 2.
So, No.
y=3x-2 is a function because it passes the vertical line test.
This means that for each individual x-value that we substitute for x, there is a unique individual y-value that y ends up equaling to.
Part I: sin (theta/2) = 1/2 So, theta/2 = sin inv(1/2) Part II: On the interval [0,2pi], theta/2 = 30 degrees i.e. pi/6 degrees or 150 degrees i.e. 5pi/6...
6 + 7 = 13
20 + 70 = 90
100 + 300 = 400
The 400 + 90 + 13 = 503
