PLZ HELPP

Mathematics

2 answers:

BlackZzzverrR [31]3 years ago

7 0

You're still solving the same problem and if you solved it correctly, both solutions would be the same.

777dan777 [17]3 years ago

4 0

Answer:

The correct answer should be C. You always get the same answer.

Step-by-step explanation:

When you are doing synthetic division:

Set up the synthetic division using the coefficients of the numerator and the root in the denominator. Divide using the rules for synthetic division.

When you are doing long division:

Divide x3-8x+3 by x+3 using long polynomial division.

LOng Polynomial Division is the same as Long division just the mathematical term.

Good Luck!!

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Rectangle A has length 12 and width 8. Rectangle B has length 15 and width 10. Rectangle C has length 30 and width 15.

never [62]

Vicki: 10 + 10 + 20 = 40

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50 - 40 = 10 birds

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3 years ago

Which expression is equivalent to 4x + ? o 1(-x+2) o 1(-2+ 3) -1(-x+ ) - (x + 2)

slavikrds [6]

Answer:

Definitely Option A.

When you expand the bracket of Option A... You have your equation

Which is

-1/4x + 1/2.

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3 years ago

PLEASE HELP ME WITH THIS MATH!!!!!!!!!. pLeAsE i ReAlLy NeEd SoMe HeLp

KonstantinChe [14]

Part 1) we know that
m∠5=44° m∠11=86°
m∠2=m∠5------> by vertical angles
m∠2=44°
m∠13=m∠11------> by vertical angles
m∠13=86°
m∠12+m∠13=180°-----> supplementary angles
m∠12=180-86-----> m∠12=94°
m∠14=m∠12----> by vertical angles
m∠14=94°
m∠1=m∠11----> by corresponding angles
m∠1=86°
m∠4=m∠1----> by vertical angles
m∠4=86°
m∠2+m∠1+m∠6=180
m∠6=180-(86+44)----> 50°
m∠6=50°
m∠3=m∠6----> by vertical angles
m∠3=50°
m∠8=m∠3----> by corresponding angles
m∠8=50°
m∠8+m∠7=180°-----> supplementary angles
m∠7=180-50----> 130°
m∠7=130°
m∠10=m∠6----> by corresponding angles
m∠10=50°
m∠10+m∠9=180°-----> supplementary angles
m∠9=180-50-----> 130°
m∠9=130°

the answers Part 1) are
m∠1=86°
m∠2=44°
m∠3=50°
m∠4=86°
m∠5=44°
m∠6=50°
m∠7=130°
m∠8=50°
m∠9=130°
m∠10=50°
m∠11=86°
m∠12=94°
m∠13=86°
m∠14=94°

Part 2)
a) what is m∠TPR?
in the right triangle PTR
m∠PTR+m∠TPR+m∠TRP=180° ( the sum of internal angles of triangle is equal to 180 degrees)
m∠PTR=30°
m∠TRP=90°
so
m∠TPR=180-(90+30)----> 60°

the answer Part 2a) is
m∠TPR=60°

b) what is the length in inches of segment PR?
in the right triangle PTR
sin 30=PR/TP-----> PR=TP*sin 30-----> PR=14*(1/2)----> 7 in

the answer Part 2b) is
PR=7 in

c) what is the length in inches of segment TR?
in the right triangle PTR
cos 30=TR/PT-----> TR=PT*cos 30-----> TR=14*(√3/2)---> TR=7√3 in

the answer Part 2c) is
TR=7√3 in

d) what is the length in inches of segment PQ?
in the right triangle PQR
PR=7 in
RQ=PR-----> by angle 45°
so
RQ=7 in
applying the Pythagoras Theorem
PQ²=RQ²+PR²-----> 7²+7²-----> PQ²=98-----> PQ=√98 in---> PQ=7√2 in

the answer Part 2d) is
PQ=7√2 in

Part 3) Patrice buys a block of wax in the shape of a right rectangular prism. The dimensions of the block are 20 cm by 9 cm by 8 cm.
 (a) What is the volume of the block?

volume of the prism=20*9*8-----> 1440 cm³

the answer Part 3 a) is
the volume of the block is 1440 cm³

Patrice melts the wax and creates a candle in the shape of a circular cylinder that has a diameter of 10 cm and a height of 15 cm.(b) To the nearest centimeter, what is the volume of the candle?
volume of a cylinder=pi*r²*h
diameter=10 cm
radius r=10/2----> 5 cm
h=15 cm
volume of a cylinder=pi*5²*15----> 1177.5 cm³-----> 1178 cm³

the answer Part 3b) is
the volume of the candle is 1178 cm³

Patrice decides to use the remaining wax to create a candle in the shape of a cube.(c) To the nearest centimeter, what is the length of the side of the cube?

the remaining wax=volume of the prism-volume of a cylinder
=1440-1178-----> 262 cm³

volume of a cube=b³
where b is the length side of the cube
262=b³-------b=∛262-----> b=6.40 cm-----> b=6 cm

the answer Part 3c) is
the length of the side of the cube is 6 cm

5 0

4 years ago

Winnie Bracken opened a savings account at Dallas Trust Bank on March 1. It pays 4% interest compounded quarterly. She opened he

fiasKO [112]

The compounded interest is applied to the amount in the account at end

of a period specified in the rate of compounding.