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3 years ago

Help please.........

Mathematics

2 answers:

marysya [2.9K]3 years ago

8 0

Answer is 0.75 I think lol

IrinaVladis [17]3 years ago

7 0

Im on sure but probably 0.75

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Help 10 pts!!!

goldenfox [79]

Answer:

40 ft^2

Step-by-step explanation:

lateral surface area -Slat = 24 ft^2

top surface area-Stop = 8 ft^2

bottom surface area -Sbot = 8 ft^2

24+8+8= 40

total surface area -Stot = 40 ft^2

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2 years ago

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Solve by graphing:<br> x^2-6x+9=0

irinina [24]

Hello :
the solution :x²-6x+9=0 is the x- intresept and graph of f(x) =x²-6x+9
the solution is : x=3

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3 years ago

A piece of wire 23 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral tria

AURORKA [14]

Answer:

For maximum area, all of the wire should be used to construct the square.

The minimum total area is obtained when length of the wire is 10m

Step-by-step explanation:

For maximum, we use the whole length

For minimum,

supposed the x length was used for the square,

the length of the side of the square = x/4m

Area = $\frac{x^{2} }{16}$

For the equilateral triangle, the length of the side = $\frac{23 - x}{3}$

Area = $\frac{\sqrt{3} }{4} a^{2} = \frac{\sqrt{3} }{4} (\frac{23 - x}{3} )^{2}$

Total Area = $\frac{x^{2} }{16}$ + $\frac{\sqrt{3} }{36} (23-x)^{2}$

$\frac{dA}{dx} = \frac{x}{8} - \frac{\sqrt{3} }{18} (23 - x)\\$

$\frac{d^{2}A }{dx^{2} } = \frac{1}{8} + \frac{\sqrt{3} }{18} > 0$ , therefore it is minimum

$\frac{dA}{dx} = 0 \\\\$

$\frac{x}{8} - \frac{\sqrt{3} }{18} (23 - x) = 0\\$

x = 10.00m

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3 years ago

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What is the surface area of the triangular prism?

horrorfan [7]

C)132
All you do is find the area of each flat surface and add them together.
(rectangle) A=w×h
(triangle) A=w×h/2

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3 years ago

How to find n in 38n4

Rus_ich [418]

Answer:

Step-by-step explanation:

imagine 38 n = lets say b

so b/b/b/b/b

and divide that by 38

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2 years ago