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SSSSS [86.1K]
3 years ago
15

Find the area and perimeter of the triangle

Mathematics
2 answers:
Snezhnost [94]3 years ago
6 0

ANSWER:

Area of right angled triangle = 1/2 × a × b

1/2 × 9 × 5.6

2.8 × 9

25.2in²

Perimeter = a + b + c

9in + 5.6in + 10.6in

25.2in

nlexa [21]3 years ago
5 0

Answer: 25.2

Step-by-step explanation: hope the is helps :D

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3x(2x-1)-(2x+3)(2x+3)
Alexxx [7]
The answer is negative 2x squared minus 3x
6 0
3 years ago
Give a geometric description of the following system of equations.a. 2x−4y=12 −3x+6y=−15.b. 2x−4y=12 −5x+3y=10.a. 2x−4y=12 −3x+6
Reptile [31]

Answer:

a. No solution, parallel lines.

b. One solution.

Step-by-step explanation:

Given the system of equations:

a. 2x-4y=12

-3x+6y=-15

b. 2x-4y=12

-5x+3y=10

To give a geometric description of the given system of equations.

The geometric description of a system of equations in 2 variables mean the system of equations will represent the number of lines equal to the number of equations in the system given.

i.e.

Number of planes = Number of variables

Number of lines = Number of equations in the system.

Here, we are given 2 variables and 2 equation in each system.

So, they can be represented in the xy-coordinates plane.

And the number of solutions to the system depends on the following condition.

Let the system of equations be:

A_1x+B_1y+C_1=0\\A_2x+B_2y+C_2=0

1. One solution:

There will be one solution to the system of equations,  If we have:

\dfrac{A_1}{A_2}\neq\dfrac{B_1}{B_2}

2. Infinitely Many Solutions: (Identical lines in the system)

\dfrac{A_1}{A_2}=\dfrac{B_1}{B_2}= \dfrac{C_1}{C_2}

3. No Solution:(Parallel lines)

\dfrac{A_1}{A_2}=\dfrac{B_1}{B_2}\neq\dfrac{C_1}{C_2}

Now, let us discuss the system of equations one by one:

a. 2x-4y=12 OR 2x-4y-12=0

-3x+6y=-15 OR -3x+6y+15=0

A_1 = 2, B_1 = -4, C_1 = -12\\A_2 = -3, B_2 = 6, C_2= 15

Here, the ratio:

\dfrac{A_1}{A_2}=\dfrac{B_1}{B_2} = -\dfrac{2}{3}\\\dfrac{C_1}{C_2} = -\dfrac{4}{5}

\dfrac{A_1}{A_2}=\dfrac{B_1}{B_2}\neq\dfrac{C_1}{C_2}

Therefore, no solution i.e. parallel lines.

b. 2x-4y=12 OR 2x-4y-12=0

-5x+3y=10 OR -5x+3y-10=0

A_1 = 2, B_1 = -4, C_1 = -12\\A_2 = -5, B_2 = 3, C_2 = -10

\dfrac{A_1}{A_2}= -\dfrac{2}{5}\\\dfrac{B_1}{B_2} = -\dfrac{4}{3}\\\dfrac{C_1}{C_2} = -\dfrac{6}{5}

\dfrac{A_1}{A_2}\neq\dfrac{B_1}{B_2}

So, one solution.

Kindly refer to the images attached for the graphical representation of the given system of equations.

6 0
3 years ago
A triangle has side lengths of (q+r)(q+r) centimeters, (5q-10s)(5q−10s) centimeters, and (5s-7r)(5s−7r) centimeters. Which expre
Stolb23 [73]

The expression represents the perimeter, in centimeters, of the triangle is 6q - 6r - 5s

<h3>What is the perimeter?</h3>

The formula for perimeter of a triangle is expressed as;

Perimeter = a + b + c

Where a , b and c are the lengths of its side

  • (q+r)
  • (5q-10s)
  • (5s-7r)

Now, let's substitute the values

Perimeter = (q + r) + (5q - 10s) + (5s - 7r)

expand the bracket

Perimeter = q + r + 5q - 10s + 5s - 7r

collect like terms

Perimeter = q + 5q + r - 7r -10s + 5s

Add like terms

Perimeter = 6q - 6r - 5s

Thus, the expression represents the perimeter, in centimeters, of the triangle is 6q - 6r - 5s

Learn more about perimeter here:

brainly.com/question/24571594

#SPJ1

8 0
1 year ago
JKLM is a rhombus. KM is 20 and JL is 48. Find the perimeter of the<br><br> rhombus.
anygoal [31]

Answer:

104 units

Step-by-step explanation:

Given

Shape: Rhombus

JL = 48

KM = 20

Required

Determine the perimeter

The given parameter are the diagonals of the rhombus.

The perimeter (from diagonals) is calculated as thus:

P = 2\sqrt{(JL)^2 + (KM)^2}

Substitute values for JL and KM

P = 2\sqrt{48^2 + 20^2}

P = 2\sqrt{2304 +400}

P = 2\sqrt{2704}

P = 2 * 52

P = 104

<em>Hence, the perimeter is 104 units</em>

5 0
3 years ago
Find the value of n<br><br> 3n-10<br> n=
Mars2501 [29]

10-3=N

N=7

Step-by-step explanation:

hope you like it

8 0
3 years ago
Read 2 more answers
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