Answer:
x = 40
y= 20
Step-by-step explanation:
Since this is a right triangle, we can use trig functions
sin theta = opp / hyp
sin 60 = 20 sqrt(3)/ x
x sin 60 = 20 sqrt(3)
x = 20 sqrt(3)/ sin 60
x = 20 sqrt(3)/ sqrt(3)/2
x = 20 *2
x = 40
tan theta = opp /adj
tan 60 = 20 sqrt(3)/y
y = 20 sqrt(3)/ tan 60
y = 20 sqrt(3) / sqrt(3)
y = 20
Answer:
3rd one is correct......:)
Given:
![\log (5k+4)=8r](https://tex.z-dn.net/?f=%5Clog%20%285k%2B4%29%3D8r)
To find:
The exponential form of given equation.
Solution:
We have,
![\log (5k+4)=8r](https://tex.z-dn.net/?f=%5Clog%20%285k%2B4%29%3D8r)
According to the property of the logarithm,
![\log_ax=y\Rightarrow x=a^y](https://tex.z-dn.net/?f=%5Clog_ax%3Dy%5CRightarrow%20x%3Da%5Ey)
Using the above property of the logarithm, we get
Therefore, the required equation in exponential form is
.
Hello, Trenties
Thanks for using Brainly,
If you're aloud to, I would fully recommended to graph the points and figure out if they meet or not.
Here's how to find intersections.
To find the intersection of two straight lines:
First we need the equations of the two lines. If you do not have the equations, see Equation of a line - slope/intercept form and Equation of a line - point/slope form (If one of the lines is vertical, see the section below).
Then, since at the point of intersection, the two equations will have the same values of x and y, we set the two equations equal to each other. This gives an equation that we can solve for x
We substitute that x value in one of the line equations (it doesn't matter which) and solve it for y.
This gives us the x and y coordinates of the intersection.
<em>Sources, mathoprenref</em>
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Again, Trentis, if you're having any other issues or questions I'm available.
Have a mathy day,
Emacathy