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2 years ago

Does anyone know how to find the answer to this one

Mathematics

2 answers:

Oduvanchick [21]2 years ago

5 0

Answer:

4/16 is equal to 1/4
8/8 is equal to 1

WITCHER [35]2 years ago

3 0

Answer:

C. 8 to the -12 power

Step-by-step explanation:

when dividing numbers with an exponent, if they are the same # like 8 and 8, then you just subtract the exponents so 4 - 16 = -12

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Increased by 130% is 69 ?

Setler [38]

Answer:

Step-by-step explanation:

Do you mean 130% of 69? If so then we multiply 69 by 1.3. The answer is 89.7. If you mean something else, please state your question more clearly and I'll be happy to answer it.

<h2>I'm always happy to help :)</h2>

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3 years ago

Write a plan to prove that angle 1 is congruent to angle 2

skad [1K]

Answer:

alternate interior angles

Step-by-step explanation:

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2 years ago

Which of the following groups of numbers are integers?

Alenkasestr [34]

A and C are the correct answers

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3 years ago

Read 2 more answers

An e-mail filter is planned to separate valid e-mails from spam. The word free occurs in 60% of the spam messages and only 4% of

ANEK [815]

Answer:

(a) 0.152

(b) 0.789

Step-by-step explanation:

Let's denote the events as follows:

<em>F</em> = The word free occurs in an email

<em>S</em> = The email is spam

<em>V</em> = The email is valid.

The information provided to us are:

The probability of the word free occurring in a spam message is, $P(F|S)=0.60$
The probability of the word free occurring in a valid message is, $P(F|V)=0.04$
The probability of spam messages is,

$P(S)=0.20$

First let's compute the probability of valid messages:

$P (V) = 1 - P(S)\\=1-0.20\\=0.80$

(a)

To compute the probability of messages that contains the word free use the rule of total probability.

The rule of total probability is:

$P(A)=P(A|B)P(B)+P(A|B^{c})P(B^{c})$

The probability that a message contains the word free is:

$P(F)=P(F|S)P(S)+P(F|V)P(V)\\=(0.60*0.20)+(0.04*0.80)\\=0.152\\$

The probability of a message containing the word free is 0.152

(b)

To compute the probability of messages that are spam given that they contain the word free use the Bayes' Theorem.

The Bayes' theorem is used to determine the probability of an event based on the fact that another event has already occurred. That is,

$P(A|B)=\frac{P(B|A)P(A)}{P(B)}$

The probability that a message is spam provided that it contains free is:

$P(S|F)=\frac{P(F|S)P(S)}{P(F)}\\=\frac{0.60*0.20}{0.152} \\=0.78947\\$

The probability that a message is spam provided that it contains free is approximately 0.789.

(c)

To compute the probability of messages that are valid given that they do not contain the word free use the Bayes' Theorem. That is,

$P(A|B)=\frac{P(B|A)P(A)}{P(B)}$

The probability that a message is valid provided that it does not contain free is:

$P(V|F^{c})=\frac{P(F^{c}|V)P(V)}{P(F^{c})} \\=\frac{(1-P(F|V))P(V)}{1-P(F)}\\=\frac{(1-0.04)*0.80}{1-0.152} \\=0.90566$

The probability that a message is valid provided that it does not contain free is approximately 0.906.

4 0

3 years ago

RECREATION An instructor at a swimming pool asked her students if they would be interested in a n advanced swimming course, and

vfiekz [6]

She can expect 522 people to take the advanced course.

3 0

2 years ago