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Anna35 [415]
3 years ago
5

Please help with 3 thank you!

Mathematics
1 answer:
Troyanec [42]3 years ago
7 0

Answer:

Step-by-step explanation:

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Your mom opened a college fund for you when you were born. The fund had an annual interest rate of 2.5%. When you turned 18, the
Scilla [17]
Given:
Interest = 4,275
interest rate = 2.5%
term = 18 years
Principal = ?

Interest = Principal * interest rate * term
4,275 = P * 2.5% * 18
4,275/ (2.5% * 18) = P
4,275 / 0.45 = P
9,500 = P

Your mom deposited 9,500 when you were born.
3 0
4 years ago
Aisha bought 15 apples and oranges for $9. 0. Each orange costs $0. 50, and each apple costs $0. 65. Let x represent the number
zhannawk [14.2K]

Answer:

x + y = 15

0.5x + 0.65y = 9

Step-by-step explanation:

x = number of oranges

y = number of apples

total of apples and oranges is 15 so x + y = 15

total cost of apples and oranges is $9 so 0.5x + 0.65y = 9

Calculation

y = 15 - x

0.5x + 0.65(15-x) = 9

0.5x - 0.65x + 9.75 = 9

-0.15x = - 0.75

x = 5

y = 15 - x = 15 - 5 = 10

6 0
3 years ago
If 3x - 2 = -x + 10, then x =
Kipish [7]

Answer:

3

Step-by-step explanation:

3x-2= -x+10

4x= 12

x=3

5 0
3 years ago
Read 2 more answers
Please i need a quick help with this question plz
Vadim26 [7]
257000cm^2 is the solution I think
4 0
3 years ago
If f and g are differentiable functions for all real values of x such that f(1) = 4, g(1) = 3, f '(3) = −5, f '(1) = −4, g '(1)
belka [17]

Answer:

h'(1)=0

Step-by-step explanation:

We use the definition of the derivative of a quotient:

If h(x)=\frac{f(x)}{g(x)}, then:

h'(x)=\frac{f'(x)*g(x)-f(x)*g'(x)}{(g(x))^2}

Since in our case we want the derivative of h(x) at the point x = 1, which is indicated by: h'(1), we need to evaluate the previous expression at x = 1, that is:

h'(1)=\frac{f'(1)*g(1)-f(1)*g'(1)}{(g(1))^2}

which, by replacing with the given numerical values:

f(1) =4\\g(1)=3\\f'(1)=-4\\g'(1)=-3

becomes:

h'(1)=\frac{f'(1)*g(1)-f(1)*g'(1)}{(g(1))^2}=\\=\frac{-4*3-4*(-3)}{(3)^2}=\frac{-12+12}{9} =\frac{0}{9} =0

3 0
3 years ago
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