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nikitadnepr [17]
3 years ago
15

The surface is frictionless,Two blocks in contact with each other move

Mathematics
1 answer:
lesya692 [45]3 years ago
7 0

9514 1404 393

Answer:

  55 8/39 N ≈ 55 N

Step-by-step explanation:

The net force on the 1.4 kg block is proportional to its mass. That is, the ratio of net force on that block to the net force on the total mass is the same as the ratio of the block's mass to the total mass.

  net force on 1.4 kg = (1.4 kg)/(1.4 +6.4 kg) × (64 N -15 N) = (7/39)(49 N)

  net force on 1.4 kg = 8 31/39 N

Then the force applied by the 6.4 kg mass is ...

  64 N - 8 31/39 N = 55 8/39 N ≈ 55 N . . . . applied by 6.4 kg mass

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<h3> What is the new length of the string?</h3>

We know that the current string was (8 + 3/4) feet in length. Then they add another piece that measures 4.5 feet.

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6 0
2 years ago
PLS HELP MEH IM SO CONFUSED
slega [8]

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I would try going with 12.2

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If I'm correct this is very simple.

x=15

So plug that into the equation and you get

11.00+0.08x15

which equals 12.2

So I recommend trying that out :)

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