Answer:
The position P is:
ft <u><em> Remember that the position is a vector. Observe the attached image</em></u>
Step-by-step explanation:
The equation that describes the height as a function of time of an object that moves in a parabolic trajectory with an initial velocity
is:

Where
is the initial height = 0 for this case
We know that the initial velocity is:
82 ft/sec at an angle of 58 ° with respect to the ground.
So:
ft/sec
ft/sec
Thus

The height after 2 sec is:


Then the equation that describes the horizontal position of the ball is

Where
for this case
ft / sec
ft/sec
So

After 2 seconds the horizontal distance reached by the ball is:

Finally the vector position P is:
ft
Answer:
x = -5 ±4sqrt(3)
Step-by-step explanation:
(x + 5)^2 = 48
Take the square root of each side
sqrt((x + 5)^2) = ±sqrt(48)
x+5 = ±sqrt(16*3)
x+5 = ±4sqrt(3)
Subtract 5 from each side
x = -5 ±4sqrt(3)
Answer:
4:3 or 1:0
Step-by-step explanation: