Answer:
slope(m)=5/4 and
y-intercept (c)=12
Step-by-step explanation:
here,given equation of a line is
5x-4y-1=0...eqn(i)
equation of any line parallel to line(i) is
5x-4y+k=0...eqn(ii)
since,the line(ii) passes through (-8,2)[replacing x=-8 and y=2 in eqn(ii), we get]
5*(-8)-4*2+k=0
or-40-8+k=0
•°•k=48
substituting the value of k=48 in eqn(ii),
5x-4y+48=0 is the required equation of the line.
now,
changing eqn(ii) in slope intercept form we get,
4y=5x+48
or,y=5x/4+48/4
or,y=(5/4)x+12
comparing it into y=mx+c we get,
slope(m)=5/4 and y-intercept(c)=12
