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2 years ago

20: 5/3 in lowest terms

Mathematics

2 answers:

Law Incorporation [45]2 years ago

7 0

1 2/3. Is the answer

melisa1 [442]2 years ago

6 0

I think that’s the lowest terms unless you want to get into decimals

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Of the students in your class, 12% are left-handed. What fraction of the students are left-handed? Are there more right-handed o

kvv77 [185]

The left-handed students
12% are left handed, percent means per hundred. Change percent into per 100.
12% = $\dfrac{12}{100}$

Then simplify the fraction by dividing the numerator and denominator by 4
$\dfrac{12}{100}$
= $\dfrac{12:4}{100:4}$
= $\dfrac{3}{25}$
This is the fraction showing the proportion of the left-handed students

The right-handed students
Determine the fraction showing the proportion of the right-handed students
1 - the left-handed
= 1 - $\dfrac{3}{25}$

Equalize the denominator to 25
$\dfrac{25}{25} - \dfrac{3}{25}$

Simplify
$\dfrac{21}{25}$
This is the proportion of the right-handed students

<span>Are there more right-handed or left-handed students?
There are more right-handed students than the left-handed students, because 21/25 is more than 3/25</span>

4 0

3 years ago

What is the equation of the line parallel to 3x+2y= -4 that goes through the point (4,-1)

sertanlavr [38]

Answer:

y = (-3/2)x + 7

Step-by-step explanation:

3x + 2y = -4 (rearrange to slope intercept form y = mx + b)

2y = -3x - 4

y = (-3/2) x - 2

comparing this to the general form of a linear equation : y = mx + b

we see that slope of this line (and every line that is parallel to this line),

m = -3/2

if we sub this back in to the general form, we get:

y = (-3/2)x + b

We are still missing the value of b. To find this, we are given that the point (4,1) lies on the line. We simply substitute this back into the equation and solve for b.

1 = (-3/2)4 + b

1 = -6 + b

b = 7

substituting this back into the equation:

y = (-3/2)x + 7

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Lorelle pays someone $35 to clear her driveway when it snows. She wants to buy an electric snow blower for $689 so that she can

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