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IRISSAK [1]
3 years ago
6

20: 5/3 in lowest terms

Mathematics
2 answers:
Law Incorporation [45]3 years ago
7 0
1 2/3. Is the answer
melisa1 [442]3 years ago
6 0
I think that’s the lowest terms unless you want to get into decimals
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Drag the ordered pair that are 5.5 units apart.
Alexus [3.1K]

Answer:

  (-1.5, -3.5) and (-1.5, 2)

Step-by-step explanation:

The x-coordinates in increasing order are ...

  -3, -1.5, 5

The distances between pairs of these coordinates are ...

  -1.5 -(-3) = 1.5

  5 -(-3) = 8

  5 -(-1.5) = 6.5

Clearly, any pair with x = 5 is too far away from any pair with a different x-value.

<u>∆x = 1.5</u>

If the distance between pairs is 5.5, then the distance formula tells us the y-coordinate differences for pairs with x-coordinates of -3 and -1.5 must be ...

  d = √((x2 -x1)^2 +(y2 -y1)^2)

  5.5 = √(1.5^2 +(y2 -y1)^2) . . . substitute known values

  30.25 = 2.25 +(y2 -y1)^2 . . . . square both sides

  √28 = (y2 -y1) . . . . . . . . . . . . . . subtract 2.25 and take the square root

This value is irrational. Clearly none of the y-coordinates is irrational, so there are no point pairs with x-coordinates -3 and -1.5 that are 5.5 units apart.

__

<u>∆x = 0</u>

If the x-coordinates are the same, then the y-coordinates must differ by 5.5 in order for the points to be 5.5 units apart. The coordinates in order are ...

  for x = -1.5, y = -3.5, 2, 2.5 . . . . . differences of 5.5, 6, 0.25

  for x = 5, y = -3.5, 1.5 . . . . . . . difference of 5

The only pair we can find that is 5.5 units apart is ...

  (-1.5, -3.5) and (-1.5, 2).

6 0
3 years ago
Two less than the product of a number and -5 is -42.
Helga [31]

Answer:

8

Step-by-step explanation:

(p*-5)-2=-42

-5p-2=-42

-5p=-42+2=-40

-5p/-5=-40/-5

=8

6 0
3 years ago
56+8x
Luba_88 [7]
Get the a99 ph0tomath
4 0
3 years ago
If 18 more than 3 times a number is -27, what is the number?<br> 15<br> -3<br> -15<br> 3
noname [10]
Hope this helps you!

3 0
3 years ago
Can someone pls explain and do this solution:(
Orlov [11]

Given,

SP~QP

SR~QR

In ∆SRP and ∆QRP

SP~QP (given)

SR~QR (given)

PR=PR (common)

Therefore,

∆SRP~∆QRP by SSS congruence rule.

6 0
2 years ago
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